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2 years ago

PLEASE HURRY What is the slope of the line?

Mathematics

1 answer:

fenix001 [56]2 years ago

8 0

It’s y=-3/4x-1 because it is

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Find the difference. 4 and two-fifths minus 1 and seven-tenths equals what number?

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I believe it's B or C.

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2 years ago

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A circuit board manufacturer can produce 2,000 boards per hour. How many days will it take to produce 16,500 if the company has

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3 years ago

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What’s the value of Y? <br> What’s the measure of angle A? <br> What is the measure of arc DAB

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Step-by-step explanation:

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2 years ago

Emily is buying a new mountain bike on layaway for $324 if she pays $54 each week how many weeks will it take Emily to pay for t

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2 years ago

A brick is thrown upward from the top of a building at an angle of 250 above the horizontal, and with an initial speed of 15 m/s

mojhsa [17]

Answer:

(a) 25.08 m

(b) 2.05 m

Step-by-step explanation:

Let the height of the building be 'h'.

Given:

Angle of projection is, $\theta=25$ °

Initial speed is, $u=15\ m/s$

Time of flight is, $t=3.0\ s$

(a)

Consider the vertical motion of the brick.

Vertical component of initial velocity is given as:

$u_y=u\sin\theta\\\\u_y=15\sin(25)=6.34\ m/s$

Vertical displacement of the brick is equal to the height of the building.

So, vertical displacement = $-h$ (Negative sign implies downward motion)

Acceleration is due to gravity in the downward direction. So,

Acceleration is, $g=-9.8\ m/s^2$

Now, using the following equation of motion;

$-h=u_yt+\frac{1}{2}gt^2\\-h=6.34(3)-\frac{9.8}{2}(3)^2\\\\-h=19.02-44.1\\\\-h=-25.08\\\\h=25.08\ m$

Therefore, the building is 25.08 m tall.

(b)

Let the maximum height be 'H'.

At maximum height, the vertical component of velocity is 0 as the brick stops temporarily in the vertical direction.

So, $v_y=0\ m/s$

Now, using the following equation of motion, we have:

$v_y^2=u_y^2+2gH\\\\0=(6.34)^2-2\times 9.8\times H\\\\19.6H=40.2\\\\H=\frac{40.2}{19.6}=2.05\ m$

Therefore, the maximum height of the brick is 2.05 m.

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3 years ago