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3 years ago

7

Erica, James, Stella, and Kim all did an experiment involving an electrically charged object. Who did repeated trials of his or

her experiment?

1 answer:

masha68 [24]3 years ago

7 0

The answer is D (Stella)

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What answer do i need to put in the boxes

scoundrel [369]

Y-65=3(x-49) 3 is time 49 is crushed

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3 years ago

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Please help me out with this so I can keep my kitten.

notka56 [123]

Answer:

$y = \frac{32}{3}$

Step-by-step explanation:

Firstly, move over the negative 3/4 fraction (don't forget to swap the operation i.e subtract to add):

$\frac{y}{8} = \frac{7}{12} + \frac{3}{4}$

Now, to add the two fractions, simply multiply the numerator and denominator by 3:

$\frac{3*3}{4*3} = \frac{9}{12}$

Now add this to the other fraction:

$\frac{9}{12} + \frac{7}{12} = \frac{16}{12}$

This can be simplified down by dividing both the numerator and denominator by 4:

$\frac{4}{3}$

Which now simplifies the original equation to:

$\frac{y}{8} = \frac{4}{3}$

Remove the y out of the fraction:

$\frac{1}{8}y = \frac{4}{3}$

Now multiply both sides by 8:

$(\frac{1}{8}y) * 8 = (\frac{4}{3}) * 8$

$y = \frac{4*8}{3}$

$y = \frac{32}{3}$

Hope this helps!

5 0

3 years ago

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Given segments AB and CD intersect at E.

nata0808 [166]

The length of a segment is the distance between its endpoints.

$\mathbf{AB = 3\sqrt{2}}$
AB and CD are not congruent
AB does not bisect CD
CD does not bisect AB

<u>(a) Length of AB</u>

We have:

$\mathbf{A = (1,2)}$

$\mathbf{B = (4,5)}$

The length of AB is calculated using the following distance formula

$\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

So, we have:

$\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}$

$\mathbf{AB = \sqrt{18}}$

Simplify

$\mathbf{AB = 3\sqrt{2}}$

<u>(b) Are AB and CD congruent</u>

First, we calculate the length of CD using:

$\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

Where:

$\mathbf{C = (2, 4)}$

$\mathbf{D = (2, 1)}$

So, we have:

$\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}$

$\mathbf{CD = \sqrt{9}}$

$\mathbf{CD = 3}$

By comparison

$\mathbf{CD \ne AB}$

Hence, AB and CD are not congruent

<u>(c) AB bisects CD or not?</u>

If AB bisects CD, then:

$\mathbf{AB = \frac 12 \times CD}$

The above equation is not true, because:

$\mathbf{3\sqrt 2 \ne \frac 12 \times 3}$

Hence, AB does not bisect CD

<u>(d) CD bisects AB or not?</u>

If CD bisects AB, then:

$\mathbf{CD = \frac 12 \times AB}$

The above equation is not true, because:

$\mathbf{3 \ne \frac 12 \times 3\sqrt 2}$

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0

3 years ago

Please help me with these problems; geometry is really getting on my nerves. T-T

ivolga24 [154]

For #19 part A :

By vertical angles and then same side interior angles 3x + 2x = 180
5x = 180
x = 36

For #19 part B:

You are correct with the 35, but you missed the fact that the 105 angle is supplementary with the unknown angle inside the triangle. So:

180 - 105 = 75

Then:

180 = 35 + 75 + x
180 = 110 + x
x = 70

Last question:

Do you know what the symbol means? Text me and tell me and I can answer it for you. :)

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3 years ago

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What is the distance between the points (–3, 4 and (–7, 4?<br> a. 0<br> b. 3<br> c. 4<br> d. 10?

miskamm [114]

Try graphing it to help, but since it's not a slanted line (because the y-values are the same), you just do x1-x2:

-3 - -7 = 4

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3 years ago