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Leokris [45]
3 years ago
13

Please help me expand theses and then help me factorise these brackets

Mathematics
2 answers:
-Dominant- [34]3 years ago
8 0

Answer:

-9xy+16x

Step-by-step explanation:

x(y-2)+3x(6-y)-7xy

xy-2x+18x-3xy-7xy

xy-3xy-7xy-2x+18x

-9xy+16x

melisa1 [442]3 years ago
3 0

Answer:

-9xy+16x

Step-by-step explanation:

x(y-2) +3x(6-y) -7xy

Distribute

xy -2x +18x-3xy -7xy

Combine like terms

-9xy+16x

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Which of the following expressions represents 24C12?
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A box contains 20 red marbles and 30 blue marbles. A second box contains 10 white marbles and 40 black marbles. If you choose on
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Step-by-step explanation:

3 0
3 years ago
For what value of k will the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent?​
konstantin123 [22]

Answer:

After solve the equations we get value of k=3

Step-by-step explanation:

We need to find value of k for which the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent.

If the lines are concurrent, they pass through same point.

Let:

x+2y=0--eq(1)\\ 3x-4y-10=0--eq(2)\\ 5x+ky-7=0--eq(3)

First solving equation 1 and 2 to find values of x and y

From eq(1) we find value of x and put it in eq(2)

From \ eq(1) x+2y=0\\x=-2y\\Put x=-2y \ in \ eq(2)\\3x-4y-10=0\\3(-2y)-4y-10=0 \\-6y-4y=10\\-10y=10\\y=\frac{10}{-10}\\y=-1

After solving we get value of y=-1

Now putting in eq(1) to get value of x

x+2y=0\\x+2(-1)=0\\x-2=0\\x=2

So, Value of x= 2

Now put value of x=2 and y=-1 into eq(3) to find value of k

5x+ky-7=0\\5(2)+k(-1)-7=0\\10-k-7=0\\-k+3=0\\-k=-3\\k=3

So, After solve the equations we get value of k=3

4 0
3 years ago
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