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julia-pushkina [17]
2 years ago
13

Draw a graph of Lin's distance of a function of time for this situation:

Mathematics
1 answer:
Pavlova-9 [17]2 years ago
3 0

Step-by-step explanation:

Given

Lin walks half a mile at a constant rate i.e. Lin velocity is constant. So, in the graph, it will be a straight line through the origin.

Lin is still for five minutes and after she began sprinting for the slip up to halfway i.e. Lin is accelerating or velocity is increasing for the halfway and later she started walking for the rest of the way.

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Find a unit vector in the same direction as the given vector: v = −14.5i + 2.5 j.
Elis [28]

ANSWER

-  \frac{29}{866}  \sqrt{866} i + \frac{5}{866}  \sqrt{866} j

EXPLANATION

The given vector is v = −14.5i + 2.5 j.

The magnitude of this vector is

|v|  =  \sqrt{ {( - 14.5)}^{2}  +  {2.5}^{2} }

v|  =  \sqrt{ {( - 14.5)}^{2}  +  {2.5}^{2} }

v|  =  \sqrt{ 216.5}  =  \frac{ \sqrt{866} }{2}

The unit vector in the direction of this vector is

=  \frac{v}{ |v| }

= -   \frac{14.5}{ \frac{ \sqrt{866} }{2} } i +    \frac{2.5}{ \frac{ \sqrt{866} }{2} } j

=  -  \frac{29}{866}  \sqrt{866} i + \frac{5}{866}  \sqrt{866} j

7 0
3 years ago
A sedan will drive ten miles north, 15 miles east, 13 miles south, 15 miles west, and 22 miles
pishuonlain [190]
The total distance is 75 miles
4 0
3 years ago
If you add one-third of a number to the number itself, you get 16.what is the number?
GuDViN [60]
The answer to this is 12.


One third of 12 is 4.

12+4=16

Comment if you have ANY questions!

Hope this helps!
7 0
3 years ago
Read 2 more answers
Help me out pls!!!!!!
klio [65]
It is at (2,4) hope it helps
4 0
2 years ago
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There are 3 red and 8 green balls in a bag. If you randomly choose balls one at a time, with replacement, what is the probabilit
Kaylis [27]

So, the total number of balls is 11. We want to pick 2 red balls and 1 green ball. WLOG (since order doesnt matter here), we can say he picks red, green, red. That means on his first pick, he has a \frac{3}{11} chance of picking the red ball, and he places it back in the bag. The probability of picking a green ball is \frac{8}{11}, and then he places the ball back in the bag. The probability of picking the last red ball is the same as the last red ball example, and we simply multiply the probabilities together as per the multiplication rule to get:

\frac{3}{11}\frac{3}{11}\frac{8}{11}=\frac{3*3*8}{11^3}=\frac{72}{1331}

Now, without replacement the order does matter. He picks a red ball, a red ball then a green ball. The probability of picking the first red ball is\frac{2}{11}, and the probability of picking the second red ball is \frac{1}{10} and the probability of picking the green ball is\frac{1}{9}. We want to multiply thm again, as per the multiplication rule like the last problem.

\frac{2}{11}*\frac{1}{10}*\frac{1}{9}=\frac{1}{11*5*9}=\frac{1}{495}

5 0
3 years ago
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