Question

What are the solutions to the equation? x2(x−4)(2x+5)=0

Answer 1

Answer:

x=0 or x=4 or x=  -5/2

Step-by-step explanation:

x²(x−4)(2x+5)=0

x²=0 or x-4=0 or 2x+5=0

x=0 or x=4 or x=  -5/2

Answer 2

ANSWER:

The solutions of the given equation are 0, 0, 4, $-\frac{5}{2}$

SOLUTION:

Given, equation is $x^{2}(x-4)(2 x+5)=0$

Degree of the given equation is 4, so it is a bi-quadratic equation and it will have four solutions.

$x^{2}(x-4)(2 x+5)=0$

now on simplification we get

(x)(x)(x -4)(2x +5) = 0

It is in the form of product of four terms equal to zero.

Now, let us equate each term to zero to get solutions,

x = 0, x = 0, (x – 4) = 0, (2x + 5) =0

x = 0, x = 0,x = 4, 2x = -5

x = 0, x = 0, x = 4, x= $\frac{-5}{2}$

Hence, the solutions of the given equation are 0, 0, 4, $\frac{-5}{2}$