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evablogger [386]
3 years ago
9

Find the slope of the line.

Mathematics
1 answer:
Ivanshal [37]3 years ago
4 0
(1,4) sorry that’s probably not right lmaaoaoo
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A circle is represented by the equation below: (x + 8)2 + (y − 3)2 = 100 Which statement is true?
ss7ja [257]

Answer:

The circle is centered at (-8,3) and has a diameter of 20 units

Step-by-step explanation:

we know that

The equation of a circle in center radius form is equal to

(x-h)^2+(y-k)^2=r^2

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem we have

(x+8)^2+(y-3)^2=100

so

The center is the point (-8,3)

The radius is r=\sqrt{100}=10\ units

so

The diameter is two times the radius

D=2(10)=20\ units

therefore

The circle is centered at (-8,3) and has a diameter of 20 units

8 0
4 years ago
Read 2 more answers
Randolph is trying to find the equation of a line parallel to y = '1 over 4 x − 6 in slope-intercept form that passes through th
Aleksandr [31]
So remember that paralell lines have the same slope
y=1/4x-6
1/4=slope
so we set up a new equation in slope intercept form
y=mx+b
m=slope
b=y-intercept

y=1/4x+b

one solution si (-1,5) where x=-1 and y=5
subsitute
5=1/4(-1)+b
5=-1/4+b
add 1/4 to both sides
5+1/4=21/4=b

the answer is y=1/4x+21/4


4 0
3 years ago
Read 2 more answers
What is the answer to this math problem<br> 4-3=<br> 8-9=
ivann1987 [24]

Answer:

4-3=1

8-9=-1

Step-by-step explanation:

I hope this helps

3 0
3 years ago
What is the equation of the quadratic graph with a focus of (1 ,3) and a directrix of y=1?
zimovet [89]
Check the picture below.

now, we know the directrix is at y = 1, and the focus point is at 1,3, well, notice the picture, the distance between those fellows is just 2 units.

the vertex is half-way between those fellows, therefore, the vertex will be at 1,2.

the distance "p", from the vertex to either the directrix or focus, is really just 1 unit.  Since the focus point is above the directrix, is a vertical parabola, and it opens upwards, like in the picture, and since it opens up, the "p" value is positive, or +1.

\bf \textit{parabola vertex form with focus point distance}\\\\&#10;\begin{array}{llll}&#10;4p(x- h)=(y- k)^2&#10;\\\\&#10;\boxed{4p(y- k)=(x- h)^2}&#10;\end{array}&#10;\qquad &#10;\begin{array}{llll}&#10;vertex\ ( h, k)\\\\&#10; p=\textit{distance from vertex to }\\&#10;\qquad \textit{ focus or directrix}&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;\begin{cases}&#10;h=1\\&#10;k=2\\&#10;p=1&#10;\end{cases}\implies 4(1)(y-2)=(x-1)^2\implies 4(y-2)=(x-1)^2&#10;\\\\\\&#10;y-2=\cfrac{1}{4}(x-1)^2\implies y=\cfrac{1}{4}(x-1)^2+2

4 0
3 years ago
Each picture shows a figure and its reflection. Which picture shows the line of reflection?
nikitadnepr [17]

Answer:

Bottom left

Step-by-step explanation:

The point of reflection is the bottom left one because when reflecting a figure in a line or in a point, the image is congruent to the preimage. A reflection maps every point of a figure to an image across a fixed line. The fixed line is called the line of reflection.

3 0
2 years ago
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