What is the easiest way to find the area of a trapezoids?

1 answer:

7 0

Step 1. identify the length of both bases
Step 2. Add the lengths of the bases
Step 3. Identify the height of the trapezoids
Step 4. Multiply the sum of the lengths of the bases by the height.
Step 5. Divide the results by two and then theres your answer.

You might be interested in

A bicyclist traveled with a speed of 12 km/h from a camping ground to a station, located 60 km away. Write a formula expressing

yawa3891 [41]

1. The formula expressing the dependence of the variable s on t is: s = 60 - 12t

2. the distance travelled at time t = 3.5 h is 18 Km

<h3>What is speed? </h3>

Speed is the distance travelled per unit. Mathematically, it can be expressed as:

Speed = distance / time

<h3>1. How to determine the formula expressing the dependence of the variable s on t</h3>

From the question given, bicyclist traveled with a speed of 12 km/h from a camping ground to a station, located 60 km.

Thus, we shall determine the distance travel in time t as follow

Speed = 12 Km/h
Time = t
Distance in time t = ?

Speed = distance / time

12 = distance / t

Cross multiply

Distance = 12 × t

Distance in time t = 12t

But the total distance travelled is 60 Km. Thus, the remaining distance (s) from the bicyclist to the station at time (t) will be given as:

s = 60 - 12t

Thus, the formula expressing the dependence of the variable s on t is: s = 60 - 12t

<h3>2. How to determine the distance at t = 3.5 hours</h3>

The distance at t = 3.5 hours can be obtained as illustrated below:

Time (t) = 3.5 hours
Distance (s) = ?

s = 60 - 12t

s = 60 - (12 × 3.5)

s = 60 - 42

s = 18 Km

Thus, the distance travelled at t = 3.5 hours is 18 km

Learn more about speed:

brainly.com/question/680492

#SPJ1

6 0

2 years ago

Ralph is painting the barn below, including the sides and roof. He wants to know how much paint to purchase.

grandymaker [24]

PART A

The barn is constructed by the following 2D shapes

Two triangles of height = 4' and base = 20'
Area = 2 × (0.5×4×20) = 80

Two rectangles of length = 20' and width = 15'
Area = 2 × 20 × 15 = 600

Two rectangles of length = 45' and width = 15'
Area = 2 × 45' × 15' = 1350

One base of length = 45' and width = 15'
Area = 45 × 15 = 675

Two rectangles on each on one side of the roof. We have the length = 45' but not the width. We can work out the width by using Pythagoras theorem

w² = 4² + 10²
w² = 16 + 100
w² = 116
w = √116 = 10.77

Area of the two rectangles on the roof part is = 2 ×10.77 × 45 = 969.33

Total area to paint = 969.33+675+1350+600+80 = 3674.33 ≈ 3700 (to the nearest hundreth)

PART B

Numbers of paint cans needed = 3700 ÷ 57 = 64.9 ≈ 65 cans

PART C

Total cost of paint = 65 × 23.50 = $1527.50

PART D

The barn is constructed by a cuboid and a rectangular prism

V of cuboid = length × width × height
V of cuboid = 20 × 45 × 15
V of cuboid = 13500

V of triangular prism = Area of cross section × depth
V = [0.5×4×20] × 45
V = 1800

Total volume = 1800 + 13500 = 15300