Answer:
The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 10 - 1 = 9
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of . So we have T = 3.25
The margin of error is:
M = T*s = 3.25*25 = 81
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 12,556 - 81 = 12,475 pounds
The upper end of the interval is the sample mean added to M. So it is 12,556 + 81 = 12,637 pounds.
The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.
Answer:
Reduced fraction: 14/25
Step-by-step explanation:
To write 0.56 in terms of fractions we need to multiply and divide the number by 100:
(0.56 * 100)/100 = 56/100. Then we simplify the fraction by dividing the numerator and denominator by the common factor 2 as many times as possible:
56/100 = 28/50 = 14/25
The fraction 14/25 cannot be more simplified
1 and negative 24 is the answer
Answer:
$171
Step-by-step explanation:
=PRN
950×0.06×3
hope this helps and makes sense :))
Width = 5
5x2 = 10 and the length would 13... which is 3 more inches than twice the width