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3 years ago

8

If homework is 10% of your report card average, what would your report card grade be if your homework grade was 80 and the rest

of your grades averaged out to 90?

2 answers:

vampirchik [111]3 years ago

7 0

Answer:

80

Step-by-step explanation:

because he don't do their homework with properly then he got less mark

zavuch27 [327]3 years ago

5 0

Answer:

89

Step-by-step explanation:

maths :LLLLLLLLLLLLLLL

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Ainat [17]

Answer:

X Y

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4/5 4

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Step-by-step explanation:

y=5x

We we know y we need to solve for x

X Y

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Let y =2

2 = 5x

Divide by 5

2/5 =5x/5

2/5=x

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1 5

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3 0

3 years ago

Read 2 more answers

Find 5x9 and 1x9, and add the answers.

kipiarov [429]

5*9=45
1*9=9
Then add both numbers together
45+9=54

4 0

3 years ago

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What is 8 3/4 ÷ 2 7/8 (show ur work)

xxMikexx [17]

Answer:

<em><u>see</u></em><em><u> </u></em><em><u>below</u></em><em><u>:</u></em><em><u>-</u></em>

Step-by-step explanation:

$\displaystyle{8 \frac{3}{4} \div 2 \frac{7}{8} }$

Convert the mixed fractions into improper fractions.

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$\displaystyle{ \frac{32 + 3}{4} \div \frac{16 + 7}{8} }$

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2 years ago

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he nutrition label for Oriental Spice Sauce states that one package of sauce has 1100 milligrams of sodium. To determine if the

MrRissso [65]

Answer:

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Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 40 - 1 = 39

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 39 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.99}{2} = 0.995$ . So we have T = 2.7079

The margin of error is:

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The lower end of the interval is the sample mean subtracted by M. So it is 1088.64 - 633.97 = 454.67 milligrams

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3 years ago

What percent of 16 is 10

e-lub [12.9K]

62.5 is the answer to your question

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3 years ago