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Anon25 [30]
3 years ago
15

Nathan and Steven stacked boxes on a shelf. Nathan lifted 13 boxes and Steven lifted 15 boxes. The boxes that Nathan lifted each

weighed 12 lb more than the boxes Steven lifted.
Let s represent the weight of the boxes that Steven lifted.

Which expression represents the total number of pounds Nathan lifted?
Mathematics
1 answer:
lys-0071 [83]3 years ago
6 0

Answer:pleas don’t report me I need to do an awser so I can look up more awsers I’m in a edgenuity test right now, pleas don’t report this

Step-by-step explanation:

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1 year ago
Complete the comparison: 2+7>? a. 9+4 b. 7+3 c. 10-2 d. 8+2
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3 years ago
Here are five number cards . 2,5,7,8,9 . One of the cards is removed and the mean average of the remaining four number cards is
Elodia [21]

Answer:

7

Step-by-step explanation:

Given that there are 5 number cards.

They are 2,5,7,8,9

Total of all numbers in the cards = 2+5+7+8+9= 31

One card is removed say with number x.

Now sum new would be =31-x   ..  i

Average of remaining 4 cards = 6

So sum of remaining 4 cards = 6(4) = 24 ... ii

i and ii represent the sum of remaining 4 cards. Hence they should be equal

31-x =24

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7 0
3 years ago
Which statement about the simplified binomial expansion of (a + b)", where n is a positive integer, is true?
Alja [10]

Answer:

(a+b)^n  ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + .....  +{n \choose n}a^{(0)}b^{(n)}

Step-by-step explanation:

The Given question is INCOMPLETE as the statements are not provided.

Now, let us try and solve the given expression here:

The given expression is: (a +b)^n, n > 0

Now, the BINOMIAL EXPANSION is the expansion which  describes the algebraic expansion of powers of a binomial.

Here, (a+b)^n  = \sum_{k=0}^{n}{n \choose k}a^{(n-k)}b^{(k)}

or, on simplification, the terms of the expansion are:

(a+b)^n  ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + .....  +{n \choose n}a^{(0)}b^{(n)}

The above statement holds for each  n > 0

Hence, the complete expansion for the given expression is given as above.

4 0
3 years ago
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g100num [7]

Answer:m k k

Step-by-step explanation:

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