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3 years ago

15

A rectangle is 14 inches long and 6 inches wide. Find its area. A 78 square inches B 20 square inches C 84 square inches D 26 sq

uare inches

1 answer:

Sergio039 [100]3 years ago

7 0

Answer 34 square inches

Step-by-step explanation 2+2+2+4+4+9+9

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Help!!!!!!!!!!!!!!!!!!!asappppppppppppp

gavmur [86]

the answer is 1 and 4

Start by subtracting, so on #1 subtract 5-8, 8-11, 11-14

then go up to x, -2--1, -1-0, 0-1

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3 years ago

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Y=-x^2+2x+10<br> y=x+2<br><br> Substitution<br> Need ASAP

aniked [119]

Answer:

$x_1=\frac{1+\sqrt{33} }{2},y_1=\frac{5+\sqrt{33} }{2}\\ \\ x_2=\frac{1-\sqrt{33} }{2},y_2=\frac{5-\sqrt{33} }{2}$

Explanation:

You must find the solution of the system using the substitution method.

System:

$y=-x^2+2x+10\\\\ y=x+2$

Substitute x+2 for y:

$x+2=y=-x^2+2x+10$

Pass all the terms to one side:

$x^2-2x+x+2-10\\ \\ x^2-x-8=0$

Use the quadratic formula to solve:

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}\\ \\ x=\frac{-(-1)+/-\sqrt{(-1)^2-4(1)(-8)} }{2(1)}\\ \\ x=\frac{1+/-\sqrt{1+32} }{2}$

$x_1=\frac{1+\sqrt{33} }{2}\\ \\x_2=\frac{1-\sqrt{33} }{2}$

Use y = x + 2 to find the value of y:

$y_1=2+x_1=2+\frac{1+\sqrt{33} }{2}\\ \\y_1=\frac{5+\sqrt{33} }{2} \\\\y_2=2+x_2=2+\frac{1-\sqrt{33} }{2}\\ \\ y_2=\frac{5-\sqrt{33} }{2}$

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3 years ago

How many 3 come while writing from<br>1 to 400

Bogdan [553]

Answer:

I'm pretty sure it's 195 times

Step-by-step explanation:

(3, 23, 30-39 (extra for 33), 43, 53, 63, 73, 83, 93) x 5 = 95

95 + 100 (from 300's) = 195

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3 years ago

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Find the least common multiple of the pair of polynomials.<br> 3y2 - 48 and y + 4

alexdok [17]

Step-by-step explanation:

3y2 - 48

So the least common multiple is 3

3( y2 - 16)

y + 4 there cannot be a multiple of y

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4 years ago

Don't do for points.<br><br> Don't get your account banned.<br><br> Don't be me

elena-14-01-66 [18.8K]

The last option 9,000

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3 years ago

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