Question

I don't think that there is enough info for this problem, but could someone try to help?

Answer 1

Answer:

12

Step-by-step explanation:

Rectangle : Let length = b & width = a

PQ = QR = 6

LR = QR - PL = 6 - a

ΔPQR ~ ΔMLR

In similar triangles, corresponding sides are in same ratio.

$\frac{PQ}{QR}=\frac{ML}{LR}\\\\\frac{6}{6}=\frac{a}{6-b}$

$1 =\frac{a}{6-b}$

6 - b = a

6 = a + b

a +b = 6

Perimeter of rectangle = 2*(length +width}

       = 2*(a+ b)

       = 2 * 6

       = 12