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sesenic [268]
3 years ago
10

What is the equation of the line passing through (0,0) and (1,4)

Mathematics
1 answer:
posledela3 years ago
6 0
\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 0}}\quad ,&{{ 0}})\quad 
%   (c,d)
&({{ 1}}\quad ,&{{ 4}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{4-0}{1-0}\implies 4

\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-0=4(x-0)\implies \boxed{y=4x} 
\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
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Which point on the x-axis lies on the line that passes
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Answer:

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Step-by-step explanation:

For given line AB:

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= -3/2-(-4) = -3/6 = -1/2

Equation of line AB:

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Finding equation of line that is parallel to line AB and passes through the point C(2,2):

Substituting the slope from line AB into the equation of the line

y = (-1/2)x + b.

Substituting the given point (-2,2) into the x and y values 2 = (-1/2)-2 + b.

Solving for b (the y-intercept) , we get b = 1

Substitute this value for 'b' in the slope intercept form equation y = (-1/2)x + 1.

For x-intercept of the line, we let y = 0

0 = (-1/2)x + 1

x = -1(-2/1)

x = +2

So, the point on the x-axis that lies on the line that passes

through point C and is parallel to line AB is (2,0).

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