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3 years ago

Arithmetic series help!!!!

Mathematics

1 answer:

jekas [21]3 years ago

4 0

The initial term of the sequence is 15. The common difference is 3, so the n-th term (an) is

... an = 15 + 3(n-1)

For n=14, the 14th term of the sequence is

... a14 = 15 + 3(14 -1) = 54

The sum of terms is the average of the first and last, multiplied by the number of terms:

... sum = (15 + 54)/2·14 = 7·69 = 483

The appropriate answer choice is

... 54; 483

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Solve for p: 3p-2=2p/5+p-2/3<br><br>please help ASAP<br>Best answer will be marked brainliest

Reika [66]

P=5/6

Mark brainliest please

Hope this helps you

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3 years ago

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Make a ten or hundred to add mentally 198+132

Veseljchak [2.6K]

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3 years ago

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Lina20 [59]

Answer:

i dont

Step-by-step explanation:

good luck

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3 years ago

Please help me simplify this equation!

vladimir1956 [14]

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3 0

3 years ago

Question 8b , thanks

marta [7]

Answer:

Step-by-step explanation:

$a = \frac{2b+1}{3b-1}$

b = 2/3

$2b + 1 = 2*\frac{2}{3}+1\\\\=\frac{4}{3}+1\\\\=\frac{4}{3}+\frac{3}{3}\\\\=\frac{7}{3}\\\\3b-1 = 3*\frac{2}{3}-1\\\\=2- 1 = 1\\\\\\$

$a = \frac{2b+1}{3b-1}\\\\a=\frac{\frac{7}{3}}{1}\\\\=\frac{7}{3}\\\\$

a = 7/3

$\frac{2b+1}{3b-1}=a\\\\$

Cross multiply,

2b + 1 = a*(3b - 1)

2b + 1 = a*3b - 3*a

2b + 1 = 3ab- 3a

2b = 3ab - 3a - 1

2b - 3ab = -3a - 1

b(2 - 3a) = -3a - 1

$b =\frac{-3a - 1}{2 - 3a}$

3 0

2 years ago