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Law Incorporation [45]
3 years ago
8

I need help with this question.​

Mathematics
1 answer:
elena-s [515]3 years ago
3 0

Answer:

c.25

Step-by-step explanation:

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Reshaun sells houses. He gets a 4% commission for every house he sells.This month he sold $518,000 worth of houses. How much doe
Elden [556K]

Answer:

$20,720

Step-by-step explanation:

$518,000 x 4% = $20,720

8 0
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A fish is 18 feet below the surface of the lake. The fish swims up 12 feet before diving 45 feet. What is the current depth of t
kirill [66]

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I am pretty sure the answer would be 51 feet

4 0
3 years ago
I need help with this I don’t understand this
Y_Kistochka [10]
D.1296 is the answer
4 0
3 years ago
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Determine the equations of the vertical and horizontal asymptotes, if any, for y=x^3/(x-2)^4
djverab [1.8K]

Answer:

Option a)

Step-by-step explanation:

To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.

\lim_{x\to\\2}\frac{x^3}{(x-2)^4} \\\\\\lim_{x\to\\2}\frac{2^3}{(2-2)^4}\\\\\lim_{x\to\\2}\frac{2^3}{(0)^4} = \infty

Then. x = 2 it's a vertical asintota.

To obtain the horizontal asymptote of the function take the following limit:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4}

if \lim_{x \to \infty}\frac{x^3}{(x-2)^4} = b then y = b is horizontal asymptote

Then:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4} \\\\\\lim_{x \to \infty}\frac{1}{(\infty)} = 0

Therefore y = 0 is a horizontal asymptote of f(x).

Then the correct answer is the option a) x = 2, y = 0

3 0
4 years ago
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A friend is in 5th grade math and asks you to explain exponents with example. What do you say?
Vesnalui [34]

Answer:

If my friend is in 5th grade and they need an example on exponents I would show them something like this 7 to the 3 power would be equal to 7 times 7 times 7 which also equals 343 or 4 to the 4th power would be equal to 4 times 4 times 4 times 4 which equals 256

Step-by-step explanation:

This is a simpiler way to show a younger student how to figure out exponents also. Have a great day :D  

If you need help me and my older brother both share this account.

4 0
4 years ago
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