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Masja [62]
3 years ago
5

Mathematics help needed. Which of the following statements are true regarding functions?

Mathematics
1 answer:
Evgen [1.6K]3 years ago
3 0
A and c. No horizontal line
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A sock drawer contains eight navy blue socks and five black socks with no other socks. If you reach in the drawer and take two s
Rzqust [24]

Answer:

a. the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b. the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c. the probability of either 2 navy socks is picked or one black  & one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

Step-by-step explanation:

A sock drawer contains 8 navy blue socks and 5 black socks with no other socks.

If you reach in the drawer and take two socks without looking and without replacement, what is the probability that:  

Solution:

total socks = N = 8 + 5 + 0 = 13

a) you will pick a navy sock and a black sock?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick the black sock, total number of socks left is 12.

Let B be the probability of picking a black sock again.

 P (B) = 5/12.

Then, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b) the colors of the two socks will match?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick another navy sock, total number of socks left is 12.

Let B be the probability of another navy sock again.

 P (B) = 7/12.

Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

Let D be the probability of picking a black socks first.

Then P (D) = 5/13

without replacing the black sock, will pick another black sock, total number of socks left is 12.

Let E be the probability of another black sock again.

 P (E) = 4/12.

Then, the probability of picking 2 black sock = P (D & E)

= (5/13 ) * (4/12) = 5/39 = 0.128

Now, the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c) at least one navy sock will be selected?

this means, is either you pick one navy sock and one black or two navy socks.

so, if you will pick a navy sock and a black sock, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

also, if you will pick 2 navy sock, Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

now either 2 navy socks is picked or one black  one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

4 0
3 years ago
What is a perfect squares​
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Answer:

What is a Perfect Square? A perfect square is a number which is generated by multiplying two equal integers by each other. For example, number 9 is a perfect square because it can be expressed as a product two equal integers being: 9 = 3 x 3.

Step-by-step explanation:

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a week before election day, 276 out of 450 people said they would vote for the republican candidate. if 15,240 registered voters
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Answer:

(a) \frac {276}{450}=\frac {y}{15240}

(b) We cross multiply the probability by the total voters

(c) 9347

Step-by-step explanation:

(a)

Probability of getting a republican voter is

\frac {276}{450}=\frac {138}{225}=\frac {46}{75}

\frac {276}{450}=\frac {138}{225}=\frac {46}{75}=\frac {y}{15240}

These are found by dividing the first numerator and denominator by 2, then by 3

To make it complete, the situation is therefore defined as \frac {276}{450}=\frac {y}{15240} where y is unknown value

(b)

Cross multiplication of the probability and number of voters gives the actual figure of y in the equation formed in part a of the question.

(c)

Since we have 15240 voters who plan to participate in election, we cross multiply to get the approximate number of republican voters which yields

\frac {46}{75}\times 15240=9347.2\approx 9347

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