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3 years ago

Which equation shows y = 3x - 1/5 in standard form? I will mark brainliest!!

Mathematics

1 answer:

11111nata11111 [884]3 years ago

6 0

Answer:

15x-5y=1

Step-by-step explanation:

y=3x−15

The standard form of a linear equation is Ax+By=C.

Multiply both sides by 5.

5y=5(3x−15)

Simplify 5(3x−15).

5y=15x−1

Rewrite the equation with the sides flipped.

15x−1=5y

Move all terms containing variables to the left side of the equation.

15x−5y−1=0

Add 1 to both sides of the equation.

15x−5y=1

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General Formulas and Concepts:
Algebra I

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Trigonometry

[Right Triangles Only] Pythagorean Theorem:
$\displaystyle a^2 + b^2 = c^2$

a is a leg
b is another leg
c is the hypotenuse

Step-by-step explanation:

Step 1: Define

Identify given variables.

a = 30

b = 3

c = x

Step 2: Find x

Let's solve for the general equation that allows us to find the hypotenuse:

[Pythagorean Theorem] Square root both sides [Equality Property]:
$\displaystyle \begin{aligned}a^2 + b^2 = c^2 \rightarrow c = \sqrt{a^2 + b^2}\end{aligned}$

Now that we have the formula to solve for the hypotenuse, let's figure out what x is equal to:

[Equation] Substitute in variables:
$\displaystyle \begin{aligned}c & = \sqrt{a^2 + b^2} \\x & = \sqrt{30^2 + 3^2}\end{aligned}$
Evaluate:
$\displaystyle \begin{aligned}c & = \sqrt{a^2 + b^2} \\x & = \sqrt{30^2 + 3^2} \\& = \boxed{ \sqrt{909} } \\\end{aligned}$