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3 years ago

WILL GIVE BRAINLIEST

Mathematics

1 answer:

miskamm [114]3 years ago

3 0

Answer:

A) 8 cm

Step-by-step explanation:

Cylinder Volume formula:

V = πr²h

72π = π3²h

72π = 9πh

h = (72π)/(9π)

h = 8

You might be interested in

You are interested in purchasing a new car. One of the many points you wish to consider is the resale value of the car after 5 y

lys-0071 [83]

Answer:

99% confidence interval for the true mean resale value of a 5-year-old car of this model is [$12,173.24 , $13,306.76].

Step-by-step explanation:

We are given that you manage to obtain data on 17 recently resold 5-year-old foreign sedans of the same model.

These 17 cars were resold at an average price of $ 12 comma 740 with a standard deviation of $ 800.

Firstly, the pivotal quantity for 99% confidence interval for the true mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average price = $12,740

s = sample standard deviation = $800

n = sample of cars = 17

$\mu$ = true population mean

Here for constructing 99% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.921 < $t_1_6$ < 2.921) = 0.99 {As the critical value of t at 16 degree of

freedom are -2.921 & 2.921 with P = 0.5%}

P(-2.921 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.921) = 0.99

P( $-2.921 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.921 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X-2.921 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.921 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

99% confidence interval for $\mu$ = [ $\bar X-2.921 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.921 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $12,740-2.921 \times {\frac{800}{\sqrt{17} } }$ , $12,740+2.921 \times {\frac{800}{\sqrt{17} } }$ ]

= [$12,173.24 , $13,306.76]

Therefore, 99% confidence interval for the true mean resale value of a 5-year-old car of this model is [$12,173.24 , $13,306.76].

6 0

3 years ago

Which table represents the same linear relationship as y = 3x - 2?

Trava [24]

Answer:

Table 4 represents the same linear expression as y = 3 x - 2.

Step-by-step explanation:

Here, the given expression is y = 3 x -2

So now check the any random pair of each table by putting in the given equation.

TABLE 1 : (2,-5)

y = 3x -2 ⇒ -5 = 3(2) -2

or, -5 = -4 , NOT POSSIBLE

TABLE 2 : (0,3)

y = 3x -2 ⇒ 3 = 3(0) -2

or, 3 = -2 , NOT POSSIBLE

TABLE 3 : (1,2)

y = 3x -2 ⇒ 2 = 3(1) -2

or, 2 = 1 , NOT POSSIBLE

TABLE 4 : (1,1)

y = 3x -2 ⇒ 1 = 3(1) -2

or, 1 = 1 , POSSIBLE

checking for (2,4)

4 = 3(2) - 2 ⇒4 = 4 POSSIBLE

Here, table 4 satisfies the given points in the expression y = 3x -2

Hence, it represents the same linear expression .

3 0

3 years ago

What is the improper fraction as a mixed number : 7/2

AleksAgata [21]

Answer:3 1/2
2 goes into 7 three times and leaves a remainder so you would keep the denominator and put 3 as a whole and 1 (the remainder) as the numerator

3 0

3 years ago

Kayak: $329.95, 33% off find the discount price

mafiozo [28]

Answer:

$221.07

Step-by-step explanation:

To find the discount price, you do 329.95*.67= 221.0665

221.0665 is rounded to 221.07

Hope this helps!

6 0

3 years ago

Use the four-step process to find f'(x) and then find f'(1), f'(2), and f'(3).

Soloha48 [4]

Step 1: evaluate f(x+h) and f(x)

We have

$f(x+h) = -(x+h)^2+6(x+h)-5 = -(x^2+2xh+h^2)+6x+6h-5$

$= -x^2-2xh-h^2+6x+6h-5$

And, of course,

$f(x)=-x^2+6x-5$

Step 2: evaluate f(x+h)-f(x)

$f(x+h)-f(x)=-x^2-2xh-h^2+6x+6h-5-(-x^2+6x-5)=-2xh-h^2+6h$

Step 3: evaluate (f(x+h)-f(x))/h

$\dfrac{f(x+h)-f(x)}{h}=-2x-h+6$

Step 4: evaluate the limit of step 3 as h->0

$f'(x) = \displaystyle \lim_{h\to 0} \dfrac{f(x+h)-f(x)}{h}=-2x+6$

So, we have

$f'(1) = -2\cdot 1+6 = 4,\quad f'(2) = -2\cdot 2+6 = 2,\quad f'(3) = -2\cdot 3+6 = 0$

5 0

3 years ago