Answer:
Yes and no because not all are in the y intercept it depends
Step-by-step explanation:
Answer:
A=B maybe ...
what is that symbols of a and b
Answer:
The answer is 672.
Step-by-step explanation:
To solve this problem, first let's find the surface area of the rectangular prism. To do that, multiply each dimension with each (times 2 | just in case you don't understand [what I'm talking about is down below]).
8 x 8 x 2 = 128
8 x 11 x 2 = 176
8 x 11 x 2 = 176
Then, add of the products together to find the surface area of the rectangular prism.
176 + 176 + 128 = 480
Now, let's find the surface area of the square pyramid. Now, for this particular pyramid, let's deal with the triangles first, then the square. Like we did with the rectangular prism above, multiply each dimension with each other (but dividing the product by 2 | in case you don't understand [what i'm talking about is down below]).
8 x 8 = 64.
64 ÷ 2 = 32.
SInce there are 4 triangles, multiply the quotient by 4 to find the surface area of the total number of triangles (what i'm talking about is down below).
32 x 4 = 128.
Now, let's tackle the square. All you have to do is find the area of the square.
8 x 8 = 64.
To find the surface area of the total square pyramid, add both surface areas.
128 + 64 = 192.
Finally, add both surface areas of the two 3-D shapes to find the surface area of the composite figure.
192 + 480 = 672.
Therefore, 672 is the answer.
Let <em>a</em> and <em>b</em> be the two numbers. Then
<em>a</em> + <em>b</em> = -4
<em>a b</em> = -2
Solve the second equation for <em>b</em> :
<em>b</em> = -2/<em>a</em>
Substitute this into the first equation:
<em>a</em> - 2/<em>a</em> = -4
Multiply both sides by <em>a</em> :
<em>a</em>² - 2 = -4<em>a</em>
Move 4<em>a</em> to the left side:
<em>a</em>² + 4<em>a</em> - 2 = 0
Use the quadratic formula to solve for <em>a</em> :
<em>a</em> = (-4 ± √(4² - 4(-2))) / 2
<em>a</em> = -2 ± √6
If <em>a</em> = -2 + √6, then
-2 + √6 + <em>b</em> = -4
<em>b</em> = -2 - √6
In the other case, we end up with the same numbers, but <em>a</em> and <em>b</em> are swapped.
