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Ksenya-84 [330]
3 years ago
9

PLEASEEE HELPPP!!! what is the reason for congruence

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
7 0

Answer:

ASA Hope this helped brainlest pls almost lvled up

Step-by-step explanation:

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HELP!<br><br> Simplify. Give your answer in radical form.
velikii [3]

Answer:

  10i\sqrt{5}

Step-by-step explanation:

2\sqrt{-125}=2\sqrt{(-1)(5^2)(5)}=2i\cdot 5\sqrt{5}=10i\sqrt{5}

5 0
3 years ago
Use the interactive to make a vertical line with the equation of x = 3. The line x = 3 has slope.
Sliva [168]

Answer:

Slope of equation x = 3 is not defined.

Step-by-step explanation:

The graph for equation x = 3 is attached.

As clear from the graph, x=3, is a straight line parallel to y-axis.

Slope:

  • Since the given equation of line is parallel to the y-axis and parallel lines have same slope.
  • Parallel lines have the same slope and will never intersect. Parallel lines continue, literally, forever without touching

Thus, the given equation will have the same slope as the y-axis.

The slope of y-axis is not defined.

Hence, the slope of this line is not defined.

4 0
3 years ago
Read 2 more answers
Riley bought a plant and planted it in a pot near a window in her house. The initial
Aliun [14]
Height is the correct answer
8 0
3 years ago
Read 2 more answers
How do I solve this?
Minchanka [31]

The maximum happens at x = -b/2a

x = -48/2(-16) = 3/2

Now replace x in the equation and solve for y:

y = 48(3/2) - 16(3/2)^2

y =  -72 - 36

y = 36

The maximum height is 36 feet.

4 0
4 years ago
Farmers know that driving heavy equipment on wet soil compresses the soil and injures future crops. Here are data on the "penetr
Greeley [361]

Answer:

Step-by-step explanation:

Hello!

To see if driving heavy equipment on wet soil compresses it causing harm to future crops, the penetrability of two types of soil were measured:

Sample 1: Compressed soil

X₁: penetrability of a plot with compressed soil.

n₁= 20 plots

X[bar]₁= 2.90

S₁= 0.14

Sample 2: Intermediate soil

X₂: penetrability of a plot with intermediate soil.

n₂= 20 (with outlier) n₂= 19 plots (without outlier)

X[bar]₂= 3.34 (with outlier) X[bar]₂= 2.29 (without outlier)

S₂= 0.32 (with outlier) S₂= 0.24 (without outlier)

Outlier: 4.26

Assuming all conditions are met and ignoring the outlier in the second sample, you have to construct a 99% CI for the difference between the average penetration in the compressed soil and the intermediate soil. To do so, you have to use a t-statistic for two independent samples:

Parámeter of interest: μ₁-μ₂

Interval:

[(X[bar]₁-X[bar]₂)±t_{n_1+n_2-2;1-\alpha/2}*Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }]

t_{n_1+n_2-2;1-\alpha/2}= t_{20+19-2;1-(0.01/2)}= t_{37; 0.995}= 2.715

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{19*0.0196+18*0.0576}{20+19-2} }= 0.195= 0.20

[(2.90-2.29)±2.715*0.20\sqrt{\frac{1}{20} +\frac{1}{19} }]

[0.436; 0.784]

I hope this helps!

5 0
3 years ago
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