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3 years ago

What is the answer?

Mathematics

1 answer:

yulyashka [42]3 years ago

5 0

Answer:

Step-by-step explanation:

Plz mark brainliest!!!

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PLEASE HELP I WILL GIVE BRAINLIEST TO ANYONE WHO WANTS IT AFTER THEY ANSWER IT!!!!!!! PLEASE HELLP ME I NEED TO GET THE DONE STA

Aleksandr [31]

I think u have to Multiply the 100 and 0.30 and that would be 30

6 0

4 years ago

What are the coordinates of the image of vertex R after a reflection across the y-axis? (–4, 3) (4, –3) (–3, –4) (3, 4)

bogdanovich [222]

(–4, 3) (4, –3) (–3, –4) (3, 4)

this is a rather simple yet complex concept the easiest way to solve these is to do the exact opposite.

so in this instance it is refrcted across the y-axiss so we swap ONLY the x value NOT the Y ie (-4,3) would switch to (4,3)

same thing would apply if it reflected across x-axis ex (-4,-3)

If it reflect across orgin you change both signs. ex (4,-3)

ie.

(–4, 3) (4, –3) (–3, –4) (3, 4)

changes to

(4, 3) (-4, –3) (3, –4) (-3, 4)

hope it helps

6 0

4 years ago

Read 2 more answers

Mike’s mom made a batch of soup that was 5 4/10 cups. Each serving was 6/10 cups. How many servings of soup did Mike’s mom make?

Mars2501 [29]

change 5 4/10 to an improper fraction (10*5 +4)/10 = 54/10

54/10 divided by 6/10

copy dot flip

54/10* 10/6

54/6

There are 9 servings of soup

7 0

3 years ago

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Why do we use the distributive property when subtracting expressions?

nadezda [96]

The distributive properties of addition and subtraction can be used to rewrite expressions for a variety of purposes. In each case, you are distributing the outside multiplier to each number in the parentheses, so that multiplication occurs with each number before addition or subtraction occurs.

5 0

3 years ago

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In the figure below, CD bisects m∠ACB, AB=BC, m∠BEC=90°, and m∠DCE=42°. Find the measure of ∠A.

vesna_86 [32]

Answer: ∠A= $24\textdegree$

Step-by-step explanation:

Since we have given that

CD bisects m∠ACB,

⇒ m∠ACD= m∠DCB =x (say)

And, AB=BC, m∠BEC=90°, and m∠DCE=42°

So,

m∠CAD=m∠ACD

In ΔDCE,

$\angle DCE+\angle CED+\angle CDE=180\textdegree\\\\(\text{Sum of anlges in triangle is }180\textdegree)\\\\42\textdegree+90\textdegree+\angle CDE=180\textdegree\\\\132\textdegree+\angle CDE=180\textdegree\\\\\angle CDE=180\textdegree-132\textdegree\\\\+\angle CDE=48\textdegree$

Now, in ΔACD,

$x+x=48\textdegree\\\\2x=48\textdegree\\\\\text{( Sum of interior anlges is equal to exterior angles )}\\\\x=\frac{48}{2}\\\\x=24\textdegree$

Hence , ∠A= $24\textdegree$

8 0

3 years ago

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