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morpeh [17]
3 years ago
15

Can anyone help me with this question please . I need to turn this in a few minutes.

Mathematics
1 answer:
n200080 [17]3 years ago
3 0

Answer:

rip

Step-by-step explanation:

its been 5 min

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What is the distance between point A(−1, 3) and point B(−8, 3) ?
balu736 [363]

Answer:

7 units

Step-by-step explanation:

6 0
3 years ago
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What is the maximum value of P = 4x + 2y, given the constraints on x and y listed below?
Solnce55 [7]
P = 4x + 2y

additional info.
<span>x+2y  <u><</u> 10
y <u><</u> 2
x <u>></u> 0
y <u>></u> 0

y can only be 0, 1, and 2.

x + 2(0) <u><</u> 10 = x <u><</u> 10
x + 2(1) <u><</u> 10 = x + 3 <u><</u> 10 = x <u><</u> 10 - 3 = x <u><</u> 7
x + 2(2) <u><</u> 10 = x + 4 <u><</u> 10 = x < 10 - 4 = x <u><</u> 6

x = 10 ; y = 0 : P = 4(10) + 2(0) = 40 + 0 = 40
x = 7 ; y = 1 : P = 4(7) + 2(1) = 28 + 2 = 30
x = 6 ; y = 2 : P = 4(6) + 2(2) = 24 + 4 = 28

The maximum value of P is 40. Where x is 10 and y is 0.</span>
5 0
4 years ago
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Expression in fractured form
pychu [463]

Answer:

Step-by-step explanation:

for the first one it's (x + 5) x (x - 7)

second one it's  (x + 5) x (x + 7)

third one is (x - 5) x ( x + 7)

fourth one is (x -5) x (x - 7)

thats the answer

8 0
3 years ago
I need help please!!!!!
charle [14.2K]
Obtuse angle. If wrong I’m sorry lol
5 0
3 years ago
What is the value of C in the matrix equation below?
lara [203]

Given:

The matrix equation is:

\begin{bmatrix}-18&3&5\end{bmatrix}-C=\begin{bmatrix}-22&1&12\end{bmatrix}

To find:

The value of matrix C.

Solution:

Let A=\begin{bmatrix}-18&3&5\end{bmatrix},B=\begin{bmatrix}-22&1&12\end{bmatrix}. Then the given equation can be rewritten as

A-C=B

-C=B-A

C=-(B-A)

C=A-B

On substituting the values of the matrices, we get

C=\begin{bmatrix}-18&3&5\end{bmatrix}-\begin{bmatrix}-22&1&12\end{bmatrix}

C=\begin{bmatrix}-18-(-22)&3-1&5-12\end{bmatrix}

C=\begin{bmatrix}-18+22&2&-7\end{bmatrix}

C=\begin{bmatrix}-4&2&-7\end{bmatrix}

Therefore, the correct option is C.

6 0
3 years ago
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