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2 years ago

11

Which number line shows the solution set for 1-3 352

1 answer:

Andrej [43]2 years ago

8 0

-4

Step-by-step explanation:

-4 show the number of wveryshaoaknd

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How do you solve 8 -x = 20

Lunna [17]

$8-x=20\\-x=12\\x=-12$

8 0

2 years ago

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Solve the equation for y.<br> 6 = 4x + 9y

k0ka [10]

Subtract 4x from both sides
Then divide both sides by 9 to isolate y

Y=(6-4x)/9

6 0

1 year ago

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What is the average rate of change for ƒ(x) = −3x + 79 over the interval 2 ≤ x ≤ 4?

Ainat [17]

Answer:

The average rate of change is -3.

Step-by-step explanation:

Given : Function $f(x)=-3x+79$ over the interval 2 ≤ x ≤ 4.

To find : What is the average rate of change ?

Solution :

Function $f(x)=-3x+79$ over [2,4]

The rate of change is the slope of the line,

So, $\text{Rate of change}=\frac{f(4)-f(2)}{4-2}$

$f(4)=-3(4)+79$

$f(4)=-12+79$

$f(4)=67$

$f(2)=-3(2)+79$

$f(2)=-6+79$

$f(2)=73$

Substitute,

$\text{Rate of change}=\frac{67-73}{4-2}$

$\text{Rate of change}=\frac{-6}{2}$

$\text{Rate of change}=-3$

Therefore, The average rate of change is -3.

8 0

2 years ago

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**The domain of f(x) = 3x + 2 is<br> {-1 in the range?

harkovskaia [24]

Answer:

Yes

Step-by-step explanation:

Graph this function on your calculator and you will see an upwards graph, if the range (y), -1 can be mapped on the graph, it is within the range.

6 0

2 years ago

K=mv^2/2 solve for v

matrenka [14]

Answer: $v=\sqrt[]{\frac{2K}{m} }$

Step-by-step explanation:

$K=\frac{mv^2}{2}$

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;

$2*K=\frac{mv^2}{2}*2$

$2K=mv^2$

Divide by m to isolate $v^2$ .

$\frac{2K}{m}=\frac{mv^2}{m}$

$\frac{2K}{m} =v^2$

To eliminate the square and isolate v, extract the square root.

$\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}$

$\sqrt[]{\frac{2K}{m} }=v$

let's rewrite it in a way that v is in the left side.

$v=\sqrt[]{\frac{2K}{m} }$

4 0

2 years ago