1. To solve this problem you must sum the volume of the cone and the volume of the hemisphere. This means that the volumen of the prop is:
Vt=Vc+Vh
Vt is the volumen of the prop.
Vc is the volumen of the cone.
Vh is the volume of the hemisphere.
2. The volume of the cone (Vc) is:
Vc=1/3(πr²h)
r=9 in
h=14 in
π=3.14
4. Then, you have:
Vc=(3.14)(9 in)²(14 in)/3
Vc=3560.76 in³/3
Vc=1186.92
5. The volume of the hemisphere (Vh) is:
Vh=2/3(πr³)
π=3.14
r=9 in
6. Then, you have:
Vh=(2)(3.14)(9 in)³/3
Vh=4578.12 in³/3
Vh=1526.04 in³
7. Finally, the volumen of the prop (Vt) is:
Vt=Vc+Vh
Vt=1186.92 in³+1526.04 in³
Vt=2713.0 in³
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What is the volume of the prop?
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The volume of the prop is 2713.0 in³
Answer:
The best estimate is 6
Step-by-step explanation:
1. Convert 1 3/4 to a whole fraction
7/4
2. Reciprocate 7/4
4/7
3. Multiply 90/7 by 4/7
360/49
4. Simplify/Solve
7.3
5. The best estimate is 6
If I am wrong please forgive and tell me in the comment section below otherwise bu-bye.
is the correct answer.
PEMDAS
4*5= 20
18 divided by 3 = 6
4 + 6 + 20 = 26
14, because 2x7=14. Every gift box uses 2 feet on ribbon. There are 7 gift boxes, so she needs 2+2+2+2+2+2+2 length of ribbon.
