(x+6)^(1/2)-5=x+1
(x+6)^(1/2)=x+6
((x+6)^(1/2))^2=(x+6)^2
x+6=x^2+12x+36
0=x^2+11x+30
(-11+(11^2-4(1)(30))^(1/2))/2
(-11+((1)^(1/2))/2
(-11+1)/2=-5
(-11-1)/2=-6
((-6)+6)^1/2-5=(-6)+1
(0^(1/2))-5=-5
-6 is non-extraneous
((-5)+6)^1/2-5=(-5)+1
(1^1/2)-5=-4
1-5=-4
-4=-4
-5 is non-extraneous
Answer: it’s 2
Step-by-step explanation:
C) if you multiply it you get w^2 + 7w +11w+77, which is w^2+18w+77
2.64575131106 I don’t know if you need to round the answer or not
Answer:
C
Step-by-step explanation:
Given
6(x + 4) = 2(y + 5) ← distribute parenthesis on both sides of the equation
6x + 24 = 2y + 10 ( subtract 10 from both sides )
6x + 14 = 2y ( divide all terms by 2 )
3x + 7 = y, hence
y = 3x + 7 → C
