Graphing (y=x+6) (y=-2x-3)
1 answer:
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Answer:
The area of quadrilateral ABCD is 139 unit^2.
Step-by-step explanation:
Given:
Quadrilateral ABCD whose vertices are A(1,1) B(7,-3) C(12,2) D(7,21).
Now, to find the area.
The coordinates of the quadrilateral are A(1,1), B(7,-3), C(12,2), D(7,21).
So, to find the area we need to bisect the quadrilateral ABCD and get the triangles ABC and ADC and then calculate their areas:
In Δ ABC:
Now, to get the area of triangle ABC:
On solving we get:
In Δ ADC:
Now, to get the area of triangle ADC:
On solving it by same process as above we get:
Now, to get the area of the quadrilateral we add the areas of the triangles ABC and ADC:
Therefore, area of quadrilateral ABCD is 139 unit^2.
The first thing we are going to do for this case is to rewrite the function correctly.
We have then:
For power properties we have:
Canceling similar terms we have:
Doing the calculations we have:
Answer:
The result of the expression is:
A 972
We have then:
For power properties we have:
Canceling similar terms we have:
Doing the calculations we have:
Answer:
The result of the expression is:
A 972