Complete question is;
A skull cleaning factory cleans animal skulls and other types of animals using flesh eating Beatles. The factory owner started with only 13 adult beetles.
After 35 days, the beetle population grew to 26 adult beetles. How long did it take before the beetle population was 13,000 beetles?
Answer:
349 days.
Step-by-step explanation:
We are given;
Initial amount of adult beetles; A_o = 13
Amount of adult beetles after 35 days; A_35 = 26
Thus can be solved using the exponential formua;
A_t = A_o × e^(kt)
Where A_t is the amount after time t, t is the time and k is a constant.
Plugging in the relevant values;
26 = 13 × e^(35k)
e^(35k) = 26/13
e^(35k) = 2
35k = In 2
35k = 0.6931
k = 0.6931/35
k = 0.0198
Now,when the beetle population is 12000,we can find the time from;
13000 = 13 × e^(k × 0.0198)
e^(k × 0.0198) = 13000/13
e^(k × 0.0198) = 1000
0.0198k = In 1000
0.0198k = 6.9078
k = 6.9078/0.0198
k ≈ 349 days.
Is where the line is horizontal
1 =< x <= 6
Its B
Answer:
4√3
Step-by-step explanation:
The distance formula applies. It tells you ...
distance = √((x2 -x1)² +(y2 -y1)²)
Filling in the given values, you have ...
distance = √((-√32 -(-4√2))² +(2√3 -(-√12))²)
= √((-4√2+4√2)² +(2√3 +2√3)²)
= √(0 + (4√3)²)
distance = 4√3
___
We make use of the fact that ...
Answer:
the probability that all tomatoes are sold is 0.919 (91.9%)
Step-by-step explanation:
since the random variable X= number of tomatoes that are demanded, is normally distributed we can make the standard random variable Z such that:
Z=(X-μ)/σ = (83 - 125)/30 = -1.4
where μ= expected value of X= mean of X (since X is normally distributed) , σ=standard deviation of X
then all tomatoes are sold if the demand surpasses 83 tomatos , therefore
P(X>83) = P(Z>-1.4) = 1- P(Z≤-1.4)
from tables of standard normal distribution →P(Z≤-1.4)=0.081 , therefore
P(X>83) = 1- P(Z≤-1.4) = 1 - 0.081 = 0.919 (91.9%)
thus the probability that all tomatoes are sold is 0.919 (91.9%)
