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3 years ago

If a silver alloy that costs $6.75 an ounce is

Mathematics

1 answer:

Dmitriy789 [7]3 years ago

3 0

9514 1404 393

Answer:

88 ounces

Step-by-step explanation:

Let x represent the number of ounces of the less expensive alloy in the mix. Then the cost of the mix will be ...

6.75x +10(55) = 8(55+x)

110 = 1.25x . . . . . . subtract 440+6.75x

88 = x . . . . . . . . divide by 1.25

88 ounces of $6.75/oz silver must be used.

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The average amount of money spent for lunch per person in the college cafeteria is $6.35 and the standard deviation is $2.31. Su

alexdok [17]

Answer:

(6.35, 5.34)

(6.35, 0.99)

0.10253

0.3984

Step-by-step explanation:

Given that :

μ = 6.35

σ = 2.31

n = 41

What is the distribution of X?X ~ N(,)

X :

Mean of distribution = μ= 6.35

The variance = σ^2 = 2.31^2 = 5.3361 = 5.34

X ~ N = (6.35, 5.34)

What is the distribution of x¯? x¯ ~ N(,)

The mean = μ = 6.35

The standard deviation of the mean = σ/sqrt(n) = 6.35/sqrt(41) = 0.9917 = 0.99

X ~N = (6.35, 0.99)

find the probability that this patron's lunch cost is between $6.1605 and $6.757.

P(6.1605 < x < 6.757)

Obtain the standardized scores:

Z = (x - μ) / σ ; (6.1605 - 6.35) / 2.31 = - 0.082

P(Z < - 0.082) = 0.46732 (Z probability calculator)

(6.757 - 6.35) / 2.31 = 0.176

P(Z < 0.176) = 0.56985 (Z probability calculator)

P(Z < 0.176) -P(Z < - 0.082)

0.56985 - 0.46732 = 0.10253

For the group of 17 patrons, find the probability that the average lunch cost is between $6.1605 and $6.757.

P(6.1605 < x < 6.757) ; n = 17

Obtain the standardized scores:

Z = (x - μ) / σ/sqrt(n) ; (6.1605 - 6.35) / 2.31/sqrt(17) = - 0.338

P(Z < - 0.338) = 0.36768 (Z probability calculator)

(6.757 - 6.35) / 2.31/sqrt(17) = 0.726

P(Z < 0.726) = 0.76608 (Z probability calculator)

P(Z < 0.726) -P(Z < - 0.338)

0.76608 - 0.36768 = 0.3984

8 0

3 years ago

Use the Distributive Property to simplify the expression: 9(5x - 3) HEPPPPP

hichkok12 [17]

When using the distributive law
answer is: 45x-27

7 0

3 years ago

1. In the diagram below , lines a and b are paraller and cut by traversal, t of angle 3 is 120 degrees, find the measure of angl

Lelu [443]

the complete question in the attached figure

1. In the diagram below , lines a and b are parallel and cut by traversal, t of angle 3 is 120 degrees, find the measure of angle 7.

∡3=∡7------------- > corresponding angles
the answer is ∡7=120 degrees

2. in the diagram below , lines a and b are parallel and cut by traversal, t of angle 2 is 50 degrees, find the measure of angle 8.

∡2=∡8------------- > alternate exterior angles

the answer is ∡8=50 degrees

3. In the diagram below , lines a and b are parallel and cut by traversal, t of angle 6 is 50 degrees, find the measure of angle 4.

∡6=∡4------------- > alternate interior angles

the answer is ∡4=50 degrees