![f(x)=(1-x^2)^{\frac{2}{3}}\implies \cfrac{df}{dx}=\cfrac{2}{3}(1-x^2)^{-\frac{1}{3}}\implies \cfrac{df}{dx}=\cfrac{2}{3\sqrt[3]{1-x^2}}](https://tex.z-dn.net/?f=f%28x%29%3D%281-x%5E2%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7Bdf%7D%7Bdx%7D%3D%5Ccfrac%7B2%7D%7B3%7D%281-x%5E2%29%5E%7B-%5Cfrac%7B1%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7Bdf%7D%7Bdx%7D%3D%5Ccfrac%7B2%7D%7B3%5Csqrt%5B3%5D%7B1-x%5E2%7D%7D)
when it comes to a rational expression, we can get critical points from, zeroing the derivative "and" from zeroing the denominator alone, however the denominator provides critical valid points that are either "asymptotic" or "cuspics", namely that the function is not differentiable or not a "smooth line" at such spot.
if we get the critical points from the denominator on this one, we get x = ±1, both of which are cuspics. Check the picture below.
<span>Given a function, if you suspect a root lies near a specific point on the number line, you can evaluate the function at several nearby values and see whether the evaluation is positive or negative. Using a calculator, you should find two real numbers that are at distance 0.01 from one another, such that one real number evaluates positive, and the other evaluates negative. Then the interval between these values contains a root.</span>
Answer:
y=3x-4 is the slope-intercept form of the equation of a line. It is in the form y=mx+b.
m is the slope (often called "rise over run") and b is the y-intercept (the point where x=0).
The y-intercept is the point (0,-4).
We need one other point. This is where finding easy calculations pays off. How about where x=2, y=(3)(2)-4 = 2.
That's the point (2,2).
Step-by-step explanation:
tell me if you get it
Answer:
It seems like you misunderstood the instructions, though I don't blame you because they wrote it strangely. I believe that you're supposed to draw your own conclusion and then explain how you go there, rather than analyze a conclusion that was already drawn for you. If a long drive=a large fare, and you've been told that the driver has a long drive, you can draw the conclusion that "The fare will be large."
Answer:
-2(x^2+15)
Step-by-step explanation:
f(x) = −2(x − 4)^2 + 2.
Expanding (x-4)^2
(x-4)(x+4)
x(x+4)-4(x+4)
x^2+4x-4x-16
x^2-16
F(x) = -2(x^2-16)+2
-2x^2-32+2
-2x^2-30
-2(x^2+15)
