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Answer:
We conclude that the population mean is different from 10.5.
Step-by-step explanation:
We are given that a random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 11 and the sample standard deviation is 2.
<em>We have to test the claim that the population mean is 10.5.</em>
Let, NULL HYPOTHESIS, :
= 10.5 {means that the population mean is 10.5}
ALTERNATE HYPOTHESIS, :
10.5 {means that the population mean is different from 10.5}
The test statistics that will be used here is One-sample t-test;
T.S. = ~
where, = sample mean = 11
s = sample standard deviation = 2
= population mean
n = sample of values = 16
So, <u>test statistics</u> = ~
= 1
<em>Now, at 0.05 significance level, t table gives a critical value of 2.131 at 15 degree of freedom. Since our test statistics is way less than the critical value of t so we have insufficient evidence to reject null hypothesis as it will not fall in the rejection region.</em>
Therefore, we conclude that the population mean is different from 10.5.
Answer: 6 feet from the pivot point
<u>Step-by-step explanation:</u>
Girl's weight x distance from center = Boy's weight x distance from center
65 (7) = 75x
6.066 = x
The boy needs to be placed 6 feet from the center (aka pivot point) which is the same as saying 1 foot from the end of the seesaw.
Answer: and
Step-by-step explanation:
In sampling distribution of .
The mean and standard deviation of the sampling distribution of p is given by :-
, where p= population proportion and n= sample size.
Let p be the population proportion of unmarried couples in the United States are mixed racially or ethnically.
As per given , we have
n = 100
p= 14% =0.14
Then, the mean and standard deviation of the sampling distribution of p will be :
Hence, the required answer : and