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ella [17]
3 years ago
8

How to do Hypotenuse ?

Mathematics
1 answer:
Anon25 [30]3 years ago
7 0

Answer:

pythagurom theorum

Step-by-step explanation:

a^2 *b^2=c^2

You might be interested in
Find the sum of the first 9 terms in the following geometric series. 64+32+16+
Dafna11 [192]

Answer:

The sum of the first 9 terms in the geometric series is 127.75

Step-by-step explanation:

In the geometric series, there is a constant ratio between each two consecutive numbers

<u>Examples:</u>

5,  10,  20,  40,  80,  ………………………. (×2)

5000,  1000,  200,  40,  …………………………(÷5)

General term (nth term) of a Geometric series is

<em>a1</em> = <em>a</em>, <em>a2</em> = <em>ar</em>, <em>a3</em> = <em>ar</em>²,  <em>a4</em> = <em>ar</em>³, ..........

an=ar^{n-1}, where

<em>a </em>is the first term

r is the constant ratio between each two consecutive terms

The sum of the first <em>n</em> terms of a Geometric series is calculated by this rule

Sn=\frac{a(1-r^{n})}{1-r}

Let us solve the question

∵ The geometric series is 64, 32, 16, .......................

∴ <em>a </em>= 64

∴ <em>r </em>= 32 ÷ 64 = 0.5

→ We need to find the sum of the first 9 terms

∴ <em>n</em> = 9

→ Substitute these values on the formula of the sum above

∴ S9=\frac{64(1-0.5^{9})}{1-0.5}

→ use the calculator to find the answer

∴ <em>S</em>9 = 127.75

 ∴ The sum of the first 9 terms in the geometric series is 127.75

7 0
3 years ago
Find the perimeter of the parallelogram with these vertices.<br> (-2, 2), (-2,-2), (3,-2), (3, -6)
vladimir1956 [14]

Answer:

20.80624847

Step-by-step explanation:

8 0
3 years ago
The common minimum multiple between <br><br> A) 2,3 and 6<br> B) 8,9 and 12<br> C) -4,2 and 8
Elan Coil [88]
A 2,3 and 6. There you go. :)
8 0
3 years ago
This is for pre calculus, please help
Harlamova29_29 [7]

Answer:

The correct answer is:

g(x)  = x+1

Step-by-step explanation:

Given that:

h(x) = f\circ g(x)= \sqrt[3]{x+3}

f(x) = \sqrt[3]{x+2}

To find:

g(x) = ?

Solution:

Let g(x)  = m

We have

f\circ g(x)= \sqrt[3]{x+3}\\OR\\f( g(x))= \sqrt[3]{x+3}...... (1)

Now, we have let:

g(x) = m\\\therefore f(g(x)) = f(m)

Putting x = in f(x), we get

f(x) = \sqrt[3]{x+2}\\\Rightarrow f(m) = \sqrt[3]{m+2}....... (2)

Comparing equation (1) and (2):

\sqrt[3]{x+3} =\sqrt[3]{m+2}

Taking cubes both sides:

x+3=m+2\\\Rightarrow m = x+3-2\\\Rightarrow m = x+1

\therefore g(x) = x+1

Hence,

The <em>correct answer </em>is:

g(x)  = x+1

5 0
3 years ago
How can you tell if there will be more than one solution for the geometric means?
lesya692 [45]

Answer: because there are different methods to it and different solutions.

Step-by-step explanation:

8 0
3 years ago
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