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ollegr [7]
3 years ago
14

The common minimum multiple between A) 2,3 and 6 B) 8,9 and 12 C) -4,2 and 8

Mathematics
1 answer:
Elan Coil [88]3 years ago
8 0
A 2,3 and 6. There you go. :)
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Triangles J K L and M N R are shown.
Dmitry [639]

Answer:

JK ≅ MN

Step-by-step explanation:

SAS states that any two sides of the angle and the angle itself, if , of two triangles are equal the two triangles are equal.

It is given that  ∠J ≅ ∠M and JL ≅ MR   i.e an angle and a side are equal. We need one more side to prove that the two triangles are equal.

If we look at the diagram closely we see that the angles J and M are formed by the sides JK & JL  and MN& MR.

It is given that JL ≅ MR  so we are left with JK ≅ MN

6 0
2 years ago
Read 2 more answers
4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.
nikitadnepr [17]

Answer:

\sum_{n=0}^9cos(\frac{\pi n}{2})=1

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}

Step-by-step explanation:

\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))

=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})

=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1

2nd

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}

=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0

3th

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))

=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}

What we use?

We use that

e^{i\pi n}=cos(\pi n)+i sin(\pi n)

and

\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}

6 0
3 years ago
Find the distance CD rounded to the nearest tenth<br> C=(10,-1) and D=(-6,3)
Fynjy0 [20]

Answer:

CD = 16.5

Step-by-step explanation:

To find the distance between two points, use this formula: L = \sqrt{(x_{2} -x_{1})^{2}+(y_{2} -y_{1})^{2} }

point C can be info set 1: (10, -1)    x₁ = 10   y₁ = -1

point D can be info set 2: (-6, 3)    x₂ = -6  y₂ = 3

Substitute the information into the formula

L = \sqrt{(x_{2} -x_{1})^{2}+(y_{2} -y_{1})^{2} }

CD = \sqrt{(-6 -10)^{2}+(3 -(-1))^{2} }    Simplify inside each bracket

CD = \sqrt{(-16)^{2}+(4)^{2} }    Square the numbers

CD = \sqrt{256+16 }     Add inside the root

CD = \sqrt{272}    Enter into calculator

CD = 16.5  Rounded to the nearest tenth, the first decimal

The distance CD is 16.5.

4 0
3 years ago
DVD Video Rentals (Refer to Example 3.) The func-
Neporo4naja [7]

Answer:

(a)\ V = \{(N,30),(R,37),(S,17)\}

(b)

Domain = \{N,R,S\}

Range = \{37,30,17\}

Step-by-step explanation:

Given

V(R) = 37,\ V(N) = 30,\  V(S) = 17

Solving (a): Set of ordered pair

A function y = f(x) is represented as (x,y)

So, the ordered pair of V is:

V = \{(R,37),(N,30),(S,17)\}

Order the alphabets in increasing order

V = \{(N,30),(R,37),(S,17)\}

Solving (b): The domain and the range

In a function \{(x_1,y_1),...,(x_n,y_n)\}

The domain and the range are represented as:

Domain = \{x_1,x_2....x_n\}

Range = \{y_1,y_2....y_n\}

So, we have:

Domain = \{N,R,S\}

Range = \{37,30,17\}

5 0
3 years ago
What is a, b, and c in this quadratic equation?
Vilka [71]
A = 7
b = -18
c = -52
Do you know what the Quadratic formula is to solve?
4 0
3 years ago
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