Well your line travels parallel to the y axis. What's perpindicular to the y axis? The x axis. So all lines perpindicular to the line traveling vertically through (4, 0) are parallel to the x axis. Now we need to find the intercept of this line, which they give you as (-2, 3).
A horizontal line that passes through -2, 3? We can put this into an equation and see what happens.
y - y1 = m(x - x1)
y - 3 = 0(x - (-2))
y - 3 = 0
y = 3
The answer is x+-6 hope this helped!!!
Answer:
0.5 < t < 2
Step-by-step explanation:
The function reaches its maximum height at ...
t = -b/(2a) = -16/(2(-16)) = 1/2 . . . . . . where a=-16, b=16, c=32 are the coefficients of f(t)
The function can be factored to find the zeros.
f(t) = -16(t^2 -1 -2) = -16(t -2)(t +1)
The factors are zero for ...
x = -1 and x = +2
The ball is falling from its maximum height during the period (0.5, 2), so that is a reasonable domain if you're only interested in the period when the ball is falling.