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AleksAgata [21]
3 years ago
14

Line j passes through points (9, 6) and (6, 8). Line k passes through points (7, 9) and (5, 6). Are line j and line k parallel o

r perpendicular?
Mathematics
1 answer:
m_a_m_a [10]3 years ago
8 0

9514 1404 393

Answer:

  perpendicular

Step-by-step explanation:

A graph shows the lines are not parallel. The lines are perpendicular.

__

j has a slope of -2/3 (down 2 for each 3 to the right)

k has a slope of 3/2 (up 3 for each 2 to the right)

These slope values have a product of 1, typical of perpendicular lines.

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Ivanshal [37]
Here is how i solved it hope it helps

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3 years ago
1) A grocer sold 5 kg of wheat flour at Rs 30 per kg and gained 20%. If he had sold
natita [175]

Answer:

given,

selling price (sp)=rs 5 ×30

=rs 150

now, gain %=20%

cost price (cp)=

\frac{sp \times 100}{100 + gain\%}

= \frac{150 \times 100}{100 + 20}

therefore cp= rs125

now,

again in 2nd case

sp= rs 27×5

therefore sp=rs 135

and cp= rs125

now, sp>cp so,

gain\% = \frac{sp - cp}{cp}  \times 100\%

or, gain=

=  \frac{135 - 125}{125}  \times 100\%

therefore gain %= 8%.... is answer

<em>hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em>

6 0
3 years ago
How do you know if a triangle doesnt have enough info to prove its congruent
Vladimir79 [104]

to prove that the triangle is congruent, it should have one of these properties:

side side side

angle angle side

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right angle   hypotenuse  side

6 0
4 years ago
On a coordinate plane, a line goes through (0, negative 1) and (3, 1). a point is at (negative 3, 0). what is the equation of th
Vitek1552 [10]

Required Equation is y = \frac{2x}{3}+2

Given: A line passing through ({x}_1,{y}_1) and ({x}_2,{y}_2)

Slope = \frac{(y_2 - y_1)}{(x_2 - x_1)} = \frac{( 1 - (-1))}{(3 - 0)}= \frac{2}{3}

Equation of line is:

Y_1(x) = \frac{2}{3}x + b

Where b is y intercept

for value of b

Y_1(0) = -1 = \frac{2}{3}*0 + b = b

⇒ b = -1

and Equation of line is:

Y_1(x) = \frac{2}{3}x + (-1)

For another parallel line that passes through the point (-3,0)

Y_2(x)= \frac{2}{3}x + c

Y_2(-3) = 0 = {2}{3}*-3 + c = -2 + c = 0

c = 2

then the equation is:

Y_2(x) = \frac{2}{3}x + 2

To learn more, visit:

brainly.com/question/14013431

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5 0
2 years ago
HELP PLEASE WILL MARK BRAINLIEST!!
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Answer:

Step-by-step explanation:

6 to the 16 power

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