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m_a_m_a [10]
1 year ago
12

On a coordinate plane, a line goes through (0, negative 1) and (3, 1). a point is at (negative 3, 0). what is the equation of th

e line that is parallel to the given line and has an x-intercept of –3? y = two-thirdsx 3 y = two-thirdsx 2 y = negative three-halvesx 3 y = –three-halvesx 2
Mathematics
1 answer:
Vitek1552 [10]1 year ago
5 0

Required Equation is y = \frac{2x}{3}+2

Given: A line passing through ({x}_1,{y}_1) and ({x}_2,{y}_2)

Slope = \frac{(y_2 - y_1)}{(x_2 - x_1)} = \frac{( 1 - (-1))}{(3 - 0)}= \frac{2}{3}

Equation of line is:

Y_1(x) = \frac{2}{3}x + b

Where b is y intercept

for value of b

Y_1(0) = -1 = \frac{2}{3}*0 + b = b

⇒ b = -1

and Equation of line is:

Y_1(x) = \frac{2}{3}x + (-1)

For another parallel line that passes through the point (-3,0)

Y_2(x)= \frac{2}{3}x + c

Y_2(-3) = 0 = {2}{3}*-3 + c = -2 + c = 0

c = 2

then the equation is:

Y_2(x) = \frac{2}{3}x + 2

To learn more, visit:

brainly.com/question/14013431

#SPJ4

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