Correct option is A. Money saved is ′ $6 ′ .
Given
Regular price of the refrigerator = $600
i) Buying the refrigerator at 20 percent off regular price
Final Discount in this case = 20% (Regular price of the refrigerator)
= 20 / 100 × 600
= $120
ii) Buying it on sale at 10 percent off regular price and an additional 10 percent off sale price
Discount for the sale = 10% (Regular price of the refrigerator)
= 10/100 × $600
= $60
Sale price of the refrigerator = Regular price of the refrigerator − Discount for sale
= $600 − $60
= $540
Final Discount in this case = 10% (Sale price of the refrigerator)
= 10/100 × $540
= $54
Money saved if we buy as (case−i) = (Final Discount in (case.i)) − (Final Discount in (case.ii))
= $60 − $54
= $6
Therefore, Money saved is ′ $6 ′ .
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The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
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70/81 is 7/81+7/9 as a proper fraction
Answer:
1 2 3 1
Step-by-step explanation:
To find the greatest common factor (GCF) between monomials, take each monomial and write it's prime factorization. Then, identify the factors common to each monomial and multiply those common factors together. Bam!
