Answer:
566 ft
Step-by-step explanation:
Given the polynomial equation
-16t² + 300t + 30 = 0
We're asked to find how high the rocket would rise in a 2 second fuse rise. This is a simple instruction that can be obtained by setting the unknown, t, in the equation to 2. Doing this, we have
-16 * 2² + 300 * 2 + 30
-16 * 4 + 600 + 30
-64 + 630 = 566 ft
Then, we can therefore conclude that the rocket will rise high up to a distance of 566 ft
Answer:
A.) y = 0.4x^(2) + 3.4x + 4
Step-by-step explanation:
x = -5
y = -3
Step-by-step explanation:
The way to get this is that you put them in fraction form 7/15 and then you make it equal to to x/100 and then divide the known part of the fraction which in this case is 100/15 which gives 6.67 (rounded). After you get that you multiply it by 7 which give you 46.69%
Step-by-step explanation:
Answer:
1/3
Step-by-step explanation:
rise over run. Find two places that land on a line I picked (0,0) and (3,1) then count up one from the first point and over 3 for the second.
