-3r and -3s are like terms True False

Tommy wished he practiced more before his violin concert. If he had practiced 1 1/2 more hours one week, he would have averaged

Nimfa-mama [501]

Answer:

30.5 hours

Step-by-step explanation:

If he were to average 8 hours PER week for 4 weeks, his total sum would have been:

8 * 4 = 32 hours

But he fell short of it. By how much?

By $1\frac{1}{2}$ hours!

So, he practiced 1 1/2 hours LESS THAN 32 hours, so his practice time is:

$32-1\frac{1}{2}\\=32-1.5\\=30.5\\=30\frac{1}{2}$

So, he practiced 30.5 hours in the 4 weeks

8 0

3 years ago

A jar contains 5 red marbles, 10 blue marbles, 1 white marble, 6 black marbles, and 3 yellow marbles. Determine the probability

Oliga [24]

Answer:

so if we make a pie chart

there's 25 marbles

it'll be 1/25 or 4% chance

a red marble is 5/ 25 or a 20% chance

say if you replace the white on the chances of you getting red will be 24% or 6/25 chance of getting red

5 0

2 years ago

When calculating total savings you must

Art [367]

Subtract 10 evertime cuz that s taxes

5 0

2 years ago

Read 2 more answers

A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang

laiz [17]

Answer-

a. Probability that three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

Solution-

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

$\binom{19}{3} = \frac{19!}{3!16!} = 969$

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

$\binom{33}{6} = \frac{33!}{6!27!} =1107568$

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

$\binom{52}{9} = \frac{52!}{9!43!} = 3679075400$

∴P(3 white candies) = $\frac{1073233392}{3679075400} =0.29$

Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

$\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}$

$=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})$

$=(969)(45)(7)(5)(15)=22892625$

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

$\binom{52}{9}=\frac{52!}{9!43!} =3679075400$

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

$\frac{22892625}{3679075400} = 0.006$

6 0

2 years ago

Annie needs $30 to buy a coat she has saved $12 and plans to work as a baby siter to earn $6 per hour which inequality shows the

tekilochka [14]

Answer:

The answer would be B. 12 + 6n is greater than or equal to 30, so n is less than or equal to 3.

explanation:

I'm bad with explaining things, but I'll try my best to explain why this is the right answer.

12 + 6n ≥ 30, so n ≤ 3

let's start with the 12 at the beginning of the inequality, Annie already has $12, so the 12 in the inequality shows the amount of money she already has being added to the $6 per hour of babysitting she needs to do (n).

Now for the + 6n, the plus is there to show that the $12 Annie already has is being added to the 6n. The 6n then represents the $6 Annie makes each hour and the n represents how many hours she needs to babysit in order to get $30. The 6 is being multiplied by the amount of hours she needs to babysit to show how much money Annie would make. Then you add on the $12 she already has.

Annie then needs at least $30, but if she makes more than $30 then she will simply have more money than needed, therefore you use the greater than or equal to sign to show that she can have more money than just $30 after working.

I hope this helps, and sorry if my explanation is hard to understand lol.

6 0

2 years ago