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Lelu [443]
3 years ago
8

-3r and -3s are like terms True False

Mathematics
1 answer:
sladkih [1.3K]3 years ago
4 0

Answer:

false

Step-by-step explanation:

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What division problem does this model represent
jeyben [28]
Answer choice B is correct
7 0
3 years ago
Please answer thank you
Alchen [17]
-x - 9 \geq 5

You want to get x by itself.

First subtract 9 from both sides of the equation.

-x - 9 \geq 5
    +9                 +9

-x \geq 14

Then divide -1 on both sides.

-x/-1 \geq 14/-1

I'm pretty sure when you divide a negative number when solving inequalities, you switch the sign.

x \leq 5

8 0
3 years ago
-6h plus 4 - 3plus h equals 11
olga55 [171]

- 6h + 4 - 3 + h = 11
So we start by combining like terms;
- 6h + h =  - 5h
4 - 3 = 1
Now we have;
- 5h + 1 = 11
We then subtract 1 from both sides;
- 5h + 1 = 11
- 5h = 10
Then we divide both sides by 5;
- 5h = 10
- 5h \div  - 5h =  h
10 \div  - 5h =  - 2
Leaving the final answer to be h = -2
5 0
3 years ago
Look at the table on texts assigned to students. A 4-column table with 3 rows titled texts assigned to students. The first colum
wel

Answer is C) 0.1 on edge.

3 0
3 years ago
Read 2 more answers
Classify each function as even, odd, or neither even nor odd.
drek231 [11]

The function

f(x) is even

g(x) is neither even nor odd

h(x) is odd

Steps:

for an even function it holds that f(-x) = f(x):

f(-x) = (-1)^6 x^6  - (-1)^4 x^ 4 = x^6 - x^4 = f(x) => f is even

for an odd h(x) it holds that h(-x) = -h(x):

h(-x) = (-1)^5x^5-(-1)^3x^3 = -(x^5-x^3) = -h(x) \implies h(x)\,\, \mbox{even}

It is easy to show that g(x) does not match any of the two possibilities above.


8 0
3 years ago
Read 2 more answers
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