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ale4655 [162]
3 years ago
8

Determine the quotient of 3 over 7 divided by 2 over 3 . 6 over 21 1 over 2 9 over 14 1 and 5 over 9

Mathematics
1 answer:
Naddika [18.5K]3 years ago
8 1

um I dunno because I need points to ask a question sorry

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Football teams toss a coin to see who will get their choice of kicking or receiving to begin a game. the probability that given
Artist 52 [7]

In a toss coin, the only result is a head or a tails. Therefore that ½ of the time you can win or ½ of the time you can lose. Therefore the probability of losing three games in a row is:

<span>P = (1/2) * (1/2) * (1/2)
P = 0.125</span>

<span>Therefore the answer is “True”.</span>

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3 years ago
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dsp73
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5 0
3 years ago
My brain is rotting and so is my mental state
geniusboy [140]

Answer:

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Step-by-step explanation:

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3 years ago
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1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING
iogann1982 [59]

If

y=\displaystyle\sum_{n=0}^\infty a_nx^n

then

y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n

The ODE in terms of these series is

\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0

\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0

\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}

We can solve the recurrence exactly by substitution:

a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0

\implies a_n=\dfrac{(-2)^n}{n!}a_0

So the ODE has solution

y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}

which you may recognize as the power series of the exponential function. Then

\boxed{y(x)=a_0e^{-2x}}

7 0
3 years ago
Write an equation of the line that passes through the given points.<br> (-1,5) and (2, - 7)
Vanyuwa [196]

Answer:

The equation of the straight line is 4x +y = 1

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given points are (-1,5) and ( 2,-7)

Slope of the line

m =\frac{y_{2}-y_{1}  }{x_{2} -x_{1} }  =\frac{-7-5}{2-(-1)}  = \frac{-12}{3} = -4

slope of the line m = -4

<u><em>Step(ii):-</em></u>

The equation of the straight line passing through the point (-1,5) and having slope 'm' = -4

y - y_{1} = m( x-x_{1} )

y - 5 = -4 ( x-(-1))

y -5 = -4 x -4

4 x + y -5 +4=0

4x +y -1 =0

<u><em>Final answer:-</em></u>

The equation of the straight line is 4x +y = 1

<u><em>  </em></u>

6 0
2 years ago
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