The value of the function h(x + 1) is -x^2 - x + 1
<h3>How to evaluate the function?</h3>
The equation of the function is given as:
h(t) =-t^2 + t + 1
The function is given as:
h(x + 1)
This means that t = x + 1
So, we substitute t = x + 1 in the equation h(t) =-t^2 + t + 1
h(x + 1) =-(x + 1)^2 + (x + 1) + 1
Evaluate the exponent
h(x + 1) =-(x^2 + 2x + 1) + x + 1 + 1
Expand the brackets
h(x + 1) = -x^2 - 2x - 1 + x + 1 + 1
Evaluate the like terms
h(x + 1) = -x^2 - x + 1
Hence, the value of the function h(x + 1) is -x^2 - x + 1
Read more about functions at:
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<u>Complete question</u>
Consider the following function definition, and calculate the value of the function
h(t) = −t2 + t + 1 h(x + 1)
20 - (4xn) = 4 is the equation
1.2 of the blue candies were damaged. Out of the 60 candies, 18 were orange (0.3 x 60) and 18 were green (0.3 x 60). 12 of the candies were red (0.2 x 60) and 12 were blue (0.2 x 60). 1.2 of these 12 blue candies were damaged (0.1 x 12).
Answer:
13
Step-by-step explanation:
13 because first you do 6-3 which equals 3 then you do 18 / 3 because of PEMDAS so you get 6 the you add 7 by 6 which equals 13!
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