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AnnZ [28]
2 years ago
5

Help ASAP please like rn

Mathematics
2 answers:
GenaCL600 [577]2 years ago
6 0

Answer:

8/35 is correct

Step-by-step explanation:

Just multiply the numerator by numerator and denominator by denominator, then simplify

Sedbober [7]2 years ago
5 0

Answer:

    14/25

hope you answer is right, but I am sorry if my answer is wrong, but have a great weekends!

- friend

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Whats the ninth term of 25 20 15 10 5
Kaylis [27]

Given:

The sequence is 25, 20, 15, 10, 5.

To find:

The ninth term of the given sequence.

Solution:

We have,

25, 20, 15, 10, 5

It is an AP because the difference between two consecutive terms are same.

Here,

First term (a) = 25

Common difference (d) = 20-25

                                       = -5

The nth terms of an AP is

a_n=a+(n-1)d

Where, a is the first term and d is the common difference.

Putting a=25, n=9 and d=-5 to get the 9th term.

a_9=25+(9-1)(-5)

a_9=25+(8)(-5)

a_9=25-40

a_9=-15

Therefore, the ninth term of the given sequence is -15.

3 0
2 years ago
There are 252 pieces of candy in a 14-ounce jar. How many pieces of candy are there per ounce in the jar?
djyliett [7]

"Per" essentially means "divided by." To find pieces per ounce, divide pieces by ounces.


(252 pieces)/(14 ounces) = (252/14) pieces/ounce = 18 pieces/ounce

5 0
3 years ago
Read 2 more answers
Drayton made this model to find the product of a 3 digit number and a 1 digit number
Paha777 [63]
400x6=2400 This is how a find a product

3 0
3 years ago
I don’t have a problem with
WARRIOR [948]

Answer:

9

Step-by-step explanation:

27 - 18 = 9

5 0
3 years ago
2. Jacqui is putting together sets of greeting cards for a school fundraiser. There are four different card options, two
Marizza181 [45]

Answer:

32

Step-by-step explanation:

The problem statement states that there are four card option two colored envelopes options and four sticker design options and as the greeting card constitutes of one type of card.one colored envelopes and one sticker design then the number of ways Jacqui arrange the greeting card sets can be calculated using the counting principle that is n1*n2*n3. So, the number of ways Jacqui arrange the greeting card sets can be calculated using the counting principle=4*2*4=32 different ways.

3 0
3 years ago
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