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3 years ago

Help. if 113.1 isnt the answer what is it

Mathematics

1 answer:

Katyanochek1 [597]3 years ago

3 0

Answer:

28.26

Step-by-step explanation:

You take the diameter and divide it in half the put the numbers in place of the variables and multiply 3.14 by 3² to get your answer.

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The answer is " $\frac{A}{(x-2)} + \frac{B}{(x+3)}$ "

Step-by-step explanation:

Let the given value is: $\frac{x-6}{x^2+x-6}$

$\to \frac{x-6}{x^2+x-6}=\frac{x-6}{x^2+(3-2)x-6}\\\\$

$=\frac{x-6}{x^2+(3-2)x-6}\\\\ =\frac{x-6}{x^2+3x-2x-6}\\\\ =\frac{x-6}{x(x+3)-2(x+3)}\\\\ =\frac{x-6}{(x+3)(x-2)}\\\\=\frac{A}{(x-2)} + \frac{B}{(x+3)}$

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3 years ago

On a coordinate grid, point V is at (6, −8) and point S is at (6, 8). The distance (in units) between points V and S is ______.

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What shape do you get when the angles of each sides are 80,100,100,80 in that order

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Read 2 more answers

Can someone please tell me what to do in this question im so confused

Sergeu [11.5K]

Im no expert but i think its
input: x,independent variable ,domain
output: y, dependent variable , range
extra: f(x) , discrete, and slope

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3 years ago

Pls help ill give brainliest

Ymorist [56]

Answer:

$\boxed {\boxed {\sf (5g^2+2)(2g-5)}}$

Step-by-step explanation:

We are given the expression:

$10g^3-25g^2+4g-10$

There are no common factors between the four numbers, however the first two have a common factor and the last two do too. Therefore, we can factor by grouping.

Group the first two terms and the last two.

$(10g^3-25g^2)+(4g-10)$

Find the greatest common factor (GCF) of the first group. It is 5g². Factor it out of the first group. You can do this by dividing both terms by the GCF.

10g³/5g²= 2g
-25g²/5g² = -5

$5g^2 (2g-5) + (4g-10)$

Repeat with the second group. The GCF is 2.

4g/2 = 2g
-10/2= -5

$5g^2 (2g-5) + 2(2g-5)$

There is another GCF: 2g-5. We can factor this out of both terms.

5g²(2g-5)/2g-5= 5g²
2(2g-5)/ 2g-5=2

$(5g^2+2)(2g-5)$

This cannot be factored further, so it is the answer.

4 0

3 years ago