Question

Pls help ill give brainliest

Answer 1

Answer:

$\boxed {\boxed {\sf (5g^2+2)(2g-5)}}$

Step-by-step explanation:

We are given the expression:

$10g^3-25g^2+4g-10$

There are no common factors between the four numbers, however the first two have a common factor and the last two do too. Therefore, we can factor by grouping.

Group the first two terms and the last two.

$(10g^3-25g^2)+(4g-10)$

Find the greatest common factor (GCF) of the first group. It is 5g². Factor it out of the first group. You can do this by dividing both terms by the GCF.

• 10g³/5g²= 2g
• -25g²/5g² = -5

$5g^2 (2g-5) + (4g-10)$

Repeat with the second group. The GCF is 2.

• 4g/2 = 2g
• -10/2= -5

$5g^2 (2g-5) + 2(2g-5)$

There is another GCF: 2g-5. We can factor this out of both terms.

• 5g²(2g-5)/2g-5= 5g²
• 2(2g-5)/ 2g-5=2

$(5g^2+2)(2g-5)$

This cannot be factored further, so it is the answer.