See how many 5s there are in 47? There are 9 and also a leftover 2 which is your remainder.<span />
Answer: Option D. 16
Solution:
If LM is a midsegment of IJK, it is joining the midpoint of the sides IJ and IK, and it's half the length of the base of the triangle (JK), then:
L is the midpoint of the side IJ, and divides it into two congruent parts:
IL=LJ
Replacing IL by 7x and LJ by 3x+4:
7x=3x+4
Solving for x: Subtracting 3x both sides of the equation:
7x-3x=3x+4-3x
Subtracting:
4x=4
Dividing both sides of the equation by 4:
4x/4=4/4
Dividing:
x=1
Then we can determine the length of LM:
LM=2x+6
Replacing x by 1 in the equation above:
LM=2(1)+6
LM=2+6
LM=8
and because LM is half the length of the base of the triangle (JK)
LM=(1/2) JK
Replacing LM by 8:
8=(1/2) JK
Multiplying both sides of the equation by 2:
2(8)=2(1/2) JK
16=(2/2) JK
16=(1) JK
16=JK
JK=16
What do u mean I’ll answer I just don’t understand wht u mean
The area of a triangle is 1/2(base x height) .
The two legs of this triangle are equal. If you position it properly,
one of them is the base, and the other one is the height.
Since it's a right triangle, A² + B² = C²
But A = B and C = 24 .
2A² = (24)²
A² = (24)² / 2
But since A=B, A² is also (base x height) of the triangle.
Area is just 1/2 of it.
Area = 1/2(24²/2) = (24)²/4 = (24/2)² = (12)² = <u>144</u> .
