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serg [7]
3 years ago
9

A force of 10 newtons act in a direction 75 above horizontal moving an object 15 meters from (0,0) to (15,0). What is the work d

one by the force?
A. 2.59 joules
B. 3.88 joules
C. 38.82 joules
D. 150.00 joules
Mathematics
2 answers:
givi [52]3 years ago
4 0

Answer:

C

Step-by-step explanation:

i think

Alinara [238K]3 years ago
3 0

Answer:

C. 38.82 on edge

Step-by-step explanation:

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the sum of two numbers is 100. the sum of 8 and the larger number is equal to 5 times the smaller number. What is the smaller nu
crimeas [40]

Answer:

x=82

y=18

Step-by-step explanation:

x+y=100

8+x=5y

5 0
2 years ago
Question 78 find the value of x
gladu [14]

For this case we have that by definition, the volume of a parallelepiped is given by:

V = l * w * h

Where:

l: It's the long

w: It is the width

h: It's the height

From the figure we have the following data:

V = 975 \ ft ^ 3\\h = 9 \ ft\\w = 4ft\\x =?

We must find the value of the length of the parallelepiped:

975 = x * 4 * 9\\975 = 36x\\x = \frac {975} {36}\\x = 27.083

Answer:

x = 27.1 \ ft

5 0
2 years ago
What is the result when 12x^3+17x^2+21x+10 is divided by 3x +2?
ruslelena [56]

Answer:4x>2+3x+5

Step-by-step explanation:

12x>3+8x>2+9x>2+21x+10

12x>3+8x>2+9x>2+6x+15×10

4x^2(3x+2)+9x^2×6x

4x^2(3x+2)+3x(3x+2)+15x+10

4x^2(3x+2)3x(3x+2)+5(3x+2)

Cancel

3x+2(4×^2+3x+5)

_____________

3x+2

4x^2+3x+5

5 0
3 years ago
sals sporting goods company plans to sell items at a local football staduim. They will sell two items that have the home team’s
lakkis [162]

12h + 20t = income

1.5(h + t) + 7h + 9t + 500 = expenses

12h + 20t - 1.5(h + t) + 7h + 9t + 500 > 0

4 0
2 years ago
Can I please have help with question 2) a and b
Ulleksa [173]

Answer:

\frac{10\sqrt{6} }{3} and \frac{11\sqrt{3} }{3}

Step-by-step explanation:

(a)

A = \frac{1}{2} × 4\sqrt{2} × \frac{5}{\sqrt{3} }

   = 2\sqrt{2} × \frac{5}{\sqrt{3} }

   = \frac{10\sqrt{2} }{\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} } ← rationalise the denominator

= \frac{10\sqrt{6} }{3} units²

(b)

Using Pythagoras' identity in the right triangle

let hypotenuse be h , then

h² = (4\sqrt{2} )² + (\frac{5}{\sqrt{3} } )²

    = 32 + \frac{25}{3}

    = \frac{96}{3} + \frac{25}{3}

    = \frac{121}{3} ( take the square root of both sides )

h = \sqrt{\frac{121}{3} } = \frac{11}{\sqrt{3} } × \frac{\sqrt{3} }{\sqrt{3} } ← rationalise the denominator

h = \frac{11\sqrt{3} }{3}

 

7 0
3 years ago
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