Check the picture below.
so, notice, the intercepted arc by the inscribed angle A is the red arc there, namely arcBCD, and the one intercepted by angle C is the arcBAD in blue there.
now, both arcs take up the whole circle, namely the whole 360°, and we also know that arcBCD = 2A, whilst arcBAD = 2C.
Answer:
x=19º
x+9=28º
7x=133º
Step-by-step explanation:
x+9+x+7x=180
9x+9=180
9x=180-9
9x=171
x=19
Be just a bit clearer, please: "find the vertex."
You could either "complete the square" or use the "quadratic formula."
Here the coefficients are a=-1, b=11 and c=-18. Because a is -, the curve opens downward and the vertex is on top, representing the function's maximum.
Use the quadratic formula with the coefficients given above.
-b plus or minus sqrt(b^2-4ac)
x = -------------------------------------------
2a
Answer:
(a) No solution
(b)
![(x_1,y_1) =(-3,-3)\\(x_2,y_2) =(4,4)](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29%20%3D%28-3%2C-3%29%5C%5C%28x_2%2Cy_2%29%20%3D%284%2C4%29)
(c) ![(-6,1)](https://tex.z-dn.net/?f=%28-6%2C1%29)
Step-by-step explanation:
Given
See attachment for graph
Solving (a): Solution to p(x) and f(x)
Curve p(x) and line f(x) do not intersect.
So, there is no solution to the pair of p(x) and f(x)
Solving (b): Two solutions to f(x)
This means that we select any two point on straight line f(x)
From the line of f(x), we have:
![(x_1,y_1) =(-3,-3)\\(x_2,y_2) =(4,4)](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29%20%3D%28-3%2C-3%29%5C%5C%28x_2%2Cy_2%29%20%3D%284%2C4%29)
Solving (c): Solution to p(x) = g(x)
Here, we write out the point of intersection of p(x) and g(x)
From the graph, the point of intersection is: ![(-6,1)](https://tex.z-dn.net/?f=%28-6%2C1%29)
Answer: (-5,1)
Step-by-step explanation:
To the left 5 units turns our 0 into negative 5 (-5) and going down on the y axis by 1 is 1 instead of 2 so the new point is (-5,1)