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astraxan [27]
2 years ago
7

I’ll mark you as brainliest!

Mathematics
2 answers:
Virty [35]2 years ago
3 0

Answer:

Area of rectangle = l*b

11*9

99

I think it will help you.

yanalaym [24]2 years ago
3 0

Answer:

first is rectangle

L = 11 m

W = 9m

area = LW

area = 11 × 9

area = 99 sq.m

2nd is circle

D = 21 .6

r = 1/2 × 21.6

r = 10.8

area = 22/7 ×10.8²

area = 336.582 sq.

3rd triangle

B = 8 in

H = 4.6 in

area = 1/2 × 8 × 4.6

area = 18.4 sq.in

4th parallelogram

b = 12 in

h = 3 in

area = b × h

area = 12 × 13

area = 156 sq.in

5th trapezoid

h = 7cm

b1 = 4 cm

b2 = 10 cm

area = ½ ×7 (4 + 10

area =49 sq.cm

Step-by-step explanation:

hope this will help you

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Answer:

2/5, because 2/5 is bigger than 0.25.

Step-by-step explanation:

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3 years ago
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At the start of 2014 Tim's house was worth 100,000.
Novay_Z [31]
For this case we have a function of the form:
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 Where,
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 Substituting values we have:
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 Answer:
 
the value of his house at the start of 2018 is:
 
y = 146410
5 0
3 years ago
Simplify the expression. What classification describes the resulting polynomial? (3x^2-11x-4)-(2x^2-x-6)
Gnoma [55]

The expression can be simplified to a polynomial of degree 2.

x^2 - 10x + 2

<h3>How to simplify the expression?</h3>

Here we have the expression:

(3x^2 -11x - 4) - (2x^2 - x - 6)

We can directly simplify this by taking the variable as common factor:

(3 - 2)*x^2 + (-11 + 1)*x + (-4 + 6)\\\\x^2 - 10x + 2

This is a polynomial, as you can see, the maximum exponent is 2, so the degree of the polynomial is 2.

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2 years ago
How does a digit in the ten thousand place compare to a digit in the thousands place
Butoxors [25]
A digit in the ten thousand place has a value of 10,000 times the value of the mere digit. While a digit in the thousands place has a value 1,000 times the value of the digit. So to compare you can do 10,000 / 1,000 = 10, which means that<span> a digit in the ten thousand place values ten times what the same digit values is it is the thousand place. </span>
4 0
3 years ago
Simplify each sum or difference. State any restrictions on the variables.
maria [59]

Simplification of the equation \frac{x}{3x+9}- \frac{8}{x^{2}  +3x} is equal to (x² -24)/ 3x(x+3), restriction on the variables are x ≠0 , x≠ -3.

As given in the question,

Given equation \frac{x}{3x+9}- \frac{8}{x^{2}  +3x}

Simplify the given equation,

x/ 3(x+3) - 8/x(x+3)

= (x² - 24) / 3x(x+3)

Restriction on the variables for the above equation is,

x≠ 0 , x≠ -3

Therefore, simplification of the equation \frac{x}{3x+9}- \frac{8}{x^{2}  +3x} is equal to (x² -24)/ 3x(x+3), restriction on the variables are x ≠0 , x≠ -3.

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8 0
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