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3 years ago

I’ll mark you as brainliest!

Mathematics

2 answers:

Virty [35]3 years ago

3 0

Answer:

Area of rectangle = l*b

11*9

I think it will help you.

yanalaym [24]3 years ago

3 0

Answer:

first is rectangle

L = 11 m

W = 9m

area = LW

area = 11 × 9

area = 99 sq.m

2nd is circle

D = 21 .6

r = 1/2 × 21.6

r = 10.8

area = 22/7 ×10.8²

area = 336.582 sq.

3rd triangle

B = 8 in

H = 4.6 in

area = 1/2 × 8 × 4.6

area = 18.4 sq.in

4th parallelogram

b = 12 in

h = 3 in

area = b × h

area = 12 × 13

area = 156 sq.in

5th trapezoid

h = 7cm

b1 = 4 cm

b2 = 10 cm

area = ½ ×7 (4 + 10

area =49 sq.cm

Step-by-step explanation:

hope this will help you

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Answer:

is b

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3 years ago

I need help with this question please with an explanation ANSWER ASAP!!!!!!

rjkz [21]

The fish is 2.25 ft above the water surface.

Step-by-step explanation:

Step 1: Given expression for height of the fish above the water surface, y = -16x² + 12x where x is time in seconds. Find height after 0.375 seconds

⇒ y = -16(0.375)² + 12 × 0.375

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3 years ago

Help me on this please

lakkis [162]

Answer:

5 miles.

Step-by-step explanation:

The Pythagorean theorem $a^{2}+b^{2} =c^{2}$ will find any side length of a perpendicular triangle when two sides are known.

We substitute for a, the shortest side, a=3 and for b, the longer side, b=4 to find the slanted hypotenuse c.

$a^{2}+b^{2} =c^{2} \\3^{2}+4^{2} =c^{2} \\9+16=c^{2}\\25=c^{2}\\5=c$

The direct route is 5 miles.

5 0

3 years ago

Analyze the graph. Determine what, if any, association there is. Explain.

ss7ja [257]

answer with explanation:

From the scatter plot we may observe that the data points follow a parabolic path.Hence, the association between the points is non-linear also, the data points follow a quadratic association.

Also, when we make a quadratic curve around these data points we see that all of the data points will be closely related to the curve.

Hence, there is a strong association between the data points.

4 0

3 years ago

Read 2 more answers

Pls help me in this i really need help :( :)

Andrews [41]

Hello and Good Morning/Afternoon:

Let's take this problem step-by-step:

First off, let's write the line in point-slope form:

$\rm \hookrightarrow (y-y_0)=m(x-x_0)$

(x₀, y₀) any random point on the line
'm' is the value of the slope

Let's calculate the slope:

$\rm \hookrightarrow Slope = \frac{y_2-y_1}{x_2-x_1}$

(x₁, y₁): any random point on the line ⇒ (-2, -6)
(x₂,y₂): any random point on the line that is not (x₁, y₁) ⇒ (2, -3)

$\rm \hookrightarrow slope = \frac{-3--6}{2--2} =\frac{3}{4}$

Now that we found the slope, let's put it into the point-slope form

⇒ we need (x₀, y₀) ⇒ let's use (2,-3)

$(y-(-3))=\frac{3}{4} (x-2)\\y+3=\frac{3}{4} (x-2)$

The equation, however, could also be put into 'slope-intercept form'

⇒ gotten by isolating the 'y' variable to the left

$y = \frac{3}{4}x-\frac{9}{2}$

Answer: $y = \frac{3}{4}x-\frac{9}{2}$ or $y+3=\frac{3}{4} (x-2)$

*Either equations work, put the one that you are the most familiar with

Hope that helps!

#LearnwithBrainly

5 0

2 years ago