3/7 x+5=8
3/7 x=3
3x=21
x=7
The answer is (2)
Answer:
12
Step-by-step explanation:
tangent opposite/adjacent. tan(29)=x/22. separate x, and you get 22tan(29), which is 12.
Given that
XY*8 = YYY ⇒⇒⇒ Where X and Y are digits
So, X is equal to one of the digits from 1 to 9
and Y is one of the digits from 1 to 9
This can be solved as following
YYY = 100Y + 10Y + Y = Y(100+10+1) = 111Y
XY*8 = 8 (10X + Y) = 80X + 8Y
∴ 80X + 8Y = 111Y
∴ 80 X = 111Y - 8 Y
∴ 80 X = 103 Y
∴ Y = 80X/103
substitute with X = 1 to 9
X = 1 ⇒⇒⇒ Y = 0.77 ⇒⇒ unacceptable
X = 2 ⇒⇒⇒ Y = 1.55 ⇒⇒ unacceptable
X = 3 ⇒⇒⇒ Y = 2.33 ⇒⇒ unacceptable
X = 4 ⇒⇒⇒ Y = 3.11 ⇒⇒ unacceptable
X = 5 ⇒⇒⇒ Y = 3.88 ⇒⇒ unacceptable
X = 6 ⇒⇒⇒ Y = 4.66 ⇒⇒ unacceptable
X = 7 ⇒⇒⇒ Y = 5.44 ⇒⇒ unacceptable
X = 8 ⇒⇒⇒ Y = 6.21 ⇒⇒ unacceptable
X = 9 ⇒⇒⇒ Y = 6.99 ⇒⇒ unacceptable
So, The is no value of Y to achieve ⇒⇒ XY * 8 = YYY
================================================
I think the problem is as following:
Given that XY8 = YYY ⇒⇒⇒ Where X and Y are digits
So, X is equal to one of the digits from 1 to 9
and Y is one of the digits from 1 to 9
This can be solved as following
YYY = 100Y + 10Y + Y = Y(100+10+1) = 111Y
XY8 = 100X + 10Y + 8
∴ 100X + 10Y + 8 = 111Y
∴ 100x + 8 = 101Y
∴ Y = (100X + 8)/101
substitute with X = 1 to 9
X = 1 ⇒⇒⇒ Y = 1.07 ⇒⇒ unacceptable
X = 2 ⇒⇒⇒ Y = 2.06 ⇒⇒ unacceptable
X = 3 ⇒⇒⇒ Y = 3.05 ⇒⇒ unacceptable
X = 4 ⇒⇒⇒ Y = 4.04 ⇒⇒ unacceptable
X = 5 ⇒⇒⇒ Y = 5.03 ⇒⇒ unacceptable
X = 6 ⇒⇒⇒ Y = 6.02 ⇒⇒ unacceptable
X = 7 ⇒⇒⇒ Y = 7.01 ⇒⇒ unacceptable
X = 8 ⇒⇒⇒ Y = 8 ⇒⇒⇒ integer ⇒⇒ the correct answer
X = 9 ⇒⇒⇒ Y =8.99 ⇒⇒ unacceptable
So, The value of Y = 8
Answer:
Area of triangle = 8.9
Area of parallelogram = 53.4 yd² (option A)
Step-by-step explanation:
✔️Area of the triangle = ½*base*height
base = 3 m
height = 5.9 m
Area of triangle = ½*3*5.9
Area of triangle = 8.85 ≈ 8.9 (nearest tenth)
✔️Area of parallelogram = base*height
base = 8.9 yd
height = 6 yd
Area of parallelogram = 8.9*6 = 53.4 yd²
Answer:
In 11 years
Step-by-step explanation:
To calculate the number of years it will take to depreciate to that value, we use the equation below; The amount after t years, with initial amount I at percentage of depreciation d can be represented as follows;
A = I( 1 - d)^t
In the question Using our definition, A = $8,500, I = $22,000, d = 8.5% = 8.5/100 = 0.085 and t = ?
Let’s plug these values;
8,500 = 22,000(1 - 0.085)^t
8,500 = 22,000(0.915)^t
divide both side by 22,000
8,500/22,000 = (0.915)^t
0.3864 = (0.915)^t
Taking the logarithm of both sides
log 0.3864 = log(0.915)^t
log 0.3864 = tlog 0.915
t = log 0.3864/log 0.915
t = 10.7 approximately 11 years
