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2 years ago

PLEASE HELP IM GOING TO FAIL WILL GIVE BRAINLESS

Mathematics

1 answer:

cluponka [151]2 years ago

6 0

Answer:

I believe 123

Step-by-step explanation:

123 since the figures are equal and C and Y are in the same position

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The lengths of brook trout caught in a certain Colorado stream are normally distributed with a mean of 14 inches and a standard

mezya [45]

Answer:

0.6563 or 65.63% of brook trout caught will be between 12 and 18 inches

Step-by-step explanation:

Mean trout length (μ) = 14 inches

Standard deviation (σ) = 3 inches

The z-score for any given trout length 'X' is defined as:

$z=\frac{X-\mu}{\sigma}$ e interval

For a length of X =12 inches:

$z=\frac{12-14}{3}\\z=-0.6667$

According to a z-score table, a score of -0.6667 is equivalent to the 25.25th percentile of the distribution.

For a length of X =18 inches:

$z=\frac{18-14}{3}\\z=1.333$

According to a z-score table, a score of 1.333 is equivalent to the 90.88th percentile of the distribution.

The proportion of trout caught between 12 and 18 inches, assuming a normal distribution, is the interval between the equivalent percentile of each length:

$P(12\leq X\leq 18) = 90.88\% - 25.25\%\\P(12\leq X\leq 18) = 65.63\%$

8 0

3 years ago

suppose a charity received a donation of $22.8 million. if this represents 58% of the charity's donated fund, what is the total

Mrac [35]

The total amount is "x", so, if 22.8 is 58%, "x" is the 100%,

$\bf \begin{array}{ccllll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
22.8&58\\
x&100
\end{array}\implies \cfrac{22.8}{x}=\cfrac{58}{100}\implies \cfrac{22.8\cdot 100}{58}=x$

6 0

3 years ago

How to do this question

Dafna11 [192]

Answer:

$0$

Step-by-step explanation:

Given:

$f(x) = \begin{cases} -x -2 &, &x < 0 \\ x &, &0 \leqslant x < 3 \\ x^2 -1 &, &3 \leqslant x \end{cases}$

Solving for $f(0)$ :

$f(0) = x \text{ when } x = 0 \\ f(0) = 0$

6 0

2 years ago

Read 2 more answers

A geometric sequence is defined by the general term tn = 75(5n), where n ∈N and n ≥ 1. What is the recursive formula of the sequ

andreyandreev [35.5K]

The correct answer is C) t₁ = 375, $t_n=5t_{n-1}$ .

From the general form,
$t_n=75(5)^n$ , we must work backward to find t₁.

The general form is derived from the explicit form, which is
$t_n=t_1(r)^{n-1}$ . We can see that r = 5; 5 has the exponent, so that is what is multiplied by every time. This gives us

$t_n=t_1(5)^{n-1}$

Using the products of exponents, we can "split up" the exponent:
$t_n=t_1(5)^n(5)^{-1}$

We know that 5⁻¹ = 1/5, so this gives us
$t_n=t_1(\frac{1}{5})(5)^n
\\
\\=\frac{t_1}{5}(5)^n$

Comparing this to our general form, we see that
$\frac{t_1}{5}=75$

Multiplying by 5 on both sides, we get that
t₁ = 75*5 = 375

The recursive formula for a geometric sequence is given by
$t_n=t_{n-1}(r)$ , while we must state what t₁ is; this gives us

$t_1=375; t_n=t_{n-1}(5)$

3 0

3 years ago

Laura randomly pulled a marble from a bag and then replaced it.

marissa [1.9K]

Answer: C. 180 times

Step-by-step explanation:

From the 60 trials, the percentage of times Laura picked a green marble was:

= 100% - Percentage of times blue and red were picked

= 100% - 25% - 15%

= 60%

If these results were repeated with 300 trials, the number of times Laura would be expected to pick green would be:

= 60% * 300

= 180 times

3 0

3 years ago