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laila [671]
3 years ago
7

A cube with a cylindrical hole cut out of the middle is shown. The edge length of the cube is 36 feet, and the circle on the fro

nt face of the cube has a diameter of 4 feet. The volume of this figure is​
Mathematics
1 answer:
Vladimir [108]3 years ago
8 0

Answer:

is cube with 34 feet and the circle on the front face of the cube has a diameter 4 feet

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X-(9x-10)+11=12x+3(-2x+ 1/3)
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X - (9x - 10) + 11 = 12x + 3(-2x + \frac{1}{3} ) equals x = \frac{10}{7} .

First, simplify brackets. / Your problem should look like: x - 9x + 10 + 11 = 12x + 3(-2x + \frac{1}{3} ). 
Second, simplify x - 9x + 10 + 11 to -8x + 10 + 11. / Your problem should look like: -8x + 10 + 11 = 12x + 3(-2x + \frac{1}{3} ).
Third, simplify -8x + 10 + 11 to -8x + 21. / Your problem should look like: -8x + 21 = 12x + 3(-2x + \frac{1}{3} ).
Fourth, expand. / Your problem should look like: -8x + 21 = 12x - 6x + 1.
Fifth, simplify 12x - 6x + 1 to 6x + 1./ Your problem should look like: -8x + 21 = 6x + 1.
Sixth, add 8x to both sides. / Your problem should look like: 21 = 6x + 1 + 8x.
Seventh, simplify 6x + 1 + 8x to 14x + 1. / Your problem should look like: 21 = 14x + 1.
Eighth, subtract 1 from both sides. / Your problem should look like: 21 - 1 = 14x.
Ninth, simplify 21 - 1 to 20. / Your problem should look like: 20 = 14x.
Tenth, divide both sides by 14. / Your problem should look like: \frac{20}{14} = x.
Eleventh, simplify \frac{20}{14} to \frac{ 10}{7} . / Your problem should look like: \frac{10}{7} = x.
Twelfth, switch sides. / Your problem should look like: x = \frac{10}{7} which is your answer.

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