Find the greatest number in which 60,90 and 120 are exactly divisible

Mathematics

1 answer:

Dvinal [7]2 years ago

3 0

Answer:

Step-by-step explanation:

To find the greatest number divisible : find the GCF

$60 = 2 \times 2 \times 3 \times 5 = 2^2 \times 3^1 \times 5^1\\\\90 = 2 \times 3 \times 3 \times 5 = 2^1 \times 3^2 \times 5\\\\120 = 2 \times 2 \times 2 \times 3 \times 5 = 2^3 \times 3^1 \times 5^1$

$Therefore \ , GCF = 2 \times 3 \times 5 = \ 30$

Therefore greatest number in which 60, 90 , 120 are divisible = 30

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There are nine water bottles in a fridge. Three full boxes are added. Two more boxes are added, both of which have one fewer bot

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The number of bottles in a full box is 12.

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Suppose, the number of bottles in a full box is $x$

So, the number of bottles in three full boxes $=3x$

Now, two more boxes are added, both of which have one fewer bottle than the other three. So, the number of bottles in these two boxes $= 2(x-1)$

As there were 9 bottles initially and now there are 67 bottles in the fridge, so the equation will be....

$9+3x+2(x-1)=67\\ \\ 9+3x+2x-2=67\\ \\ 5x+7=67\\ \\ 5x=67-7\\ \\ 5x=60\\ \\ x=\frac{60}{5}=12$

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nydimaria [60]

Given:

Tangent segment MN = 6

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Solution:

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