Question

Find the greatest number in which 60,90 and 120 are exactly divisible​

Answer 1

Answer:

30

Step-by-step explanation:

To find the greatest number divisible : find the GCF

$60 = 2 \times 2 \times 3 \times 5 = 2^2 \times 3^1 \times 5^1\\\\90 = 2 \times 3 \times 3 \times 5 = 2^1 \times 3^2 \times 5\\\\120 = 2 \times 2 \times 2 \times 3 \times 5 = 2^3 \times 3^1 \times 5^1$

$Therefore \ , GCF = 2 \times 3 \times 5 = \ 30$

Therefore greatest number in which 60, 90 , 120 are  divisible = 30