What is equation 3 in this situation because I don't understand how to find it

A department store offered a 10% discount on all humidifiers. They also stated that the first 50 customers would receive an addi

insens350 [35]

Answer:

The discount was A) $ 24.51 and B) 14.5% of the value.

Step-by-step explanation:

Since a department store offered a 10% discount on all humidifiers, and they also stated that the first 50 customers would receive an additional 5% discount off the sale price, if I purchase a humidifier that sells for $ 169 and I are among the first 50 customers, to determine what will my total discount be (a) in dollar amount and (b) in percent, the following calculation must be performed:

100 - 10 = 90

100 - 5 = 95

(169 x 0.9) x 0.95 = X

152.1 x 0.95 = X

144.49 = X

169 = 100

144.49 = X

144.49 x 100/169 = X

85.5 = X

Therefore, the discount was A) $ 24.51 and B) 14.5% of the value.

5 0

3 years ago

PLEASE HELP!!! WILL GIVE BRAINLIEST!!!!

Zepler [3.9K]

Answer:

7/20 is the scale factor

Step-by-step explanation:

We can see that Hexagon JKLMNO is bigger than Hexagon PQRSTU. This means that the scale factor is less than one.

LK is similar to QR.

QR/LK

7/20 is the scale factor.

5 0

3 years ago

Let y be a function of x such that 8x+7y=51 what is the rate of change of y with respect to x

Sauron [17]

hi im bob, bob has 8x andn 89jdm[aowdn]\madawdad

4 0

4 years ago

Read 2 more answers

PLZ HELP ME WITH THIS QUESTION!

Rashid [163]

Answer:

15

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

One method of slowing the growth of an insect population without using pesticides is to introduce into the population a number o

Zielflug [23.3K]

To be clear, the given relation between time and female population is an integral:
 $t = \int { \frac{P+S}{P[(r - 1)P - S]} } \,
dP$

The problem says that r = 1.2 and S = 400, therefore substituting:
 $t = \int { \frac{P+400}{P[(1.2 - 1)P - 400]}
} \, dP$ 

= $
\int { \frac{P+400}{P(0.2P - 400)} } \, dP$

In order to evaluate this integral, we need to write this rational function in a simpler way:
 $\frac{P+400}{P(0.2P - 400)} = \frac{A}{P} +
\frac{B}{(0.2P - 400)}$ 

where we need to evaluate A and B. In order to do so, let's calculate the LCD:
 $\frac{P+400}{P(0.2P - 400)} = \frac{A(0.2P -
400)}{P(0.2P - 400)} + \frac{BP}{P(0.2P - 400)}$ 

the denominators cancel out and we get:
P + 400 = 0.2AP - 400A + BP
 = P(0.2A + B) - 400A

The two sides must be equal to each other, bringing the system:
 $\left \{ {{0.2A + B = 1} \atop {-400A =
400}} \right.$ 

Which can be easily solved:
 $\left \{ {{B=1.2} \atop {A=-1}} \right.$ 

Therefore, our integral can be written as:
 $t = \int { \frac{P+400}{P(0.2P - 400)} } \,
dP = \int {( \frac{-1}{P} + \frac{1.2}{0.2P-400} )} \, dP$ 
= $- \int { \frac{1}{P} \, dP +
1.2\int { \frac{1}{0.2P-400} } \, dP$ 
= $- \int { \frac{1}{P} \, dP +
6\int { \frac{0.2}{0.2P-400} } \, dP$ 
= - ln |P| + 6 ln |0.2P - 400| + C

Now, let’s evaluate C by considering that at t = 0 P = 10000:
0 = - ln |10000| + 6 ln |0.2(10000) - 400| + C
C = ln |10000| - 6 ln |1600|
C = ln (10⁴) - 6 ln (2⁶·5²)
C = 4 ln (10) - 36 ln (2) - 12 ln (5) 
 Therefore, the equation relating female population with time requested is:
t = - ln |P| + 6 ln |0.2P - 400| + 4 ln (10) - 36 ln (2) - 12 ln (5)

8 0

3 years ago

What is equation 3 in this situation because I don't understand how to find it ​

What is equation 3 in this situation because I don't understand how to find it